A 0.106-A current is charging a capacitor that has square plates 4.20 cm on each side....

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Question

Answer 1

Answer #1

Solution)

Part a) We know, d*phi/dt= i/epsilon not =0.106A/(8.85*10^-12) =1.8*10^9 Vm/s

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Part b) displacement current, id= Eo*d*phi/dt

Id= (8.85*10^-12)*(1.8*10^9) = 0.016 A (Ans)

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Good luck!:)

Answer 2

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