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*please do not do problem 18! just help eith problem 17! thank you :)

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17. An initially 2.2 M aqueous solution of a weak monoprotic acid has a total ion concentration of 1.24 x 10-M when equilibri
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Answer #1

17)

Let HA be the acid.

It dissociates into H+ and A-

HA dissociates as:

HA -----> H+ + A-

2.2 0 0

2.2-x x x

Since total ionic concentration is 1.24*10^-2 M and concentration of H+ and A- would be equal, we can say that

[H+] = [A-] = 1.24*10^-2 / 2 = 6.2*10^-3 M

So,

x = 0.062 M

Use:

Ka = [H+] [A-]/[HA]

= x*x / (2.2-x)

= (6.2*10^-3 * 6.2*10^-3) / (2.2 - 6.2*10^-3)

= 1.7*10^-5

Answer: a

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