Question
I had this question for homework. "Suppose you first walk 12 meters in a direction 20° W of N, then you walk 20 meters in a direction of 40° S of W. How far are you from your starting point in meters?"

Originally, I had tried using pythagorean theorem where a was 12 and b was 20, but that was incorrect I am assuming because the triangle is not a right triangle.

I then tried the second method underneath the problem. We had discussed this method in class ( I attached the example done in class) and I believe it is the correct method to use. The answer that I got was also incorrect. I am thinking that it may be incorrect because the problem may assume North and East as the positive direction, therefore South and West would be in the negative directions and thus Ax, Bx, and By would be negative numbers instead of positive. Does this sound correct or is there an easier method?

o add 2 km 件 l. magn x1.2 a
SLDDOSL Upe Grst walk 12min a direction D wist of nocth ond uy sin(20)12m: 24172 sn (40)20 m: 1235 5521g m
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Answer #1

By using coordinate system , solution would be easy

Inx-cUrechan 12 vm 19.425 Cest) 20 In q-cli re chev 6 - 2o Sin 40-12 Sin 70 .Sa9 mC South ) し2.0m Dis plat ement : 19.489 m tant 1.579

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