Calculate the buoyant force due to the surrounding air on a man weighing 700 N ....
Calculate the buoyant force due to the surrounding air on a man weighing 700 N . Assume his average density is the same as that of water. Suppose that the density of air is 1.20 kg/m3.
Homework Answers
mass of man=700/10=70 kilograms
volume of man=mass/density=70/1000=0.07 kg/m3
buoyant force is given by
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Calculate the buoyant force due to the surrounding air on a man
weighing 700 N ....
Calculate the buoyant force due to the surrounding air on a man weighing 800 N ....
Calculate the buoyant force due to the surrounding air on a man weighing 800 N . Assume his average density is the same as that of water. Suppose that the density of air is 1.20 kg/m3. F= ?
calculate the buoyant force due to the surrounding air on a man weighing 900 N. Assume...
calculate the buoyant force due to the surrounding air on a man weighing 900 N. Assume his average density is the same as that of water. Suppose that the density of air is 1.20 kg/m3.
A)An object of volume 7.50×10−4m3 and density 1.15×103kg/m3 is completely submerged in a fluid. Calculate the...
A)An object of volume 7.50×10−4m3 and density 1.15×103kg/m3 is completely submerged in a fluid. Calculate the weight of this object. B)Calculate the buoyant force on this object if the fluid is air (density 1.20 kg/m3). C)Calculate the buoyant force on this object if the fluid is water (density 1.00×103kg/m3). D)Calculate the buoyant force on this object if the fluid is glycerin (density 1.26×103kg/m3)
Problem 1. A 15 kg ball weighs 147 N in air and weighs 118 N when...
Problem 1. A 15 kg ball weighs 147 N in air and weighs 118 N when submerged in water. The buoyant force of the water on the ball is: Problem 2. 3.5 kg of a solid copper (density: 8,920 kg/m3 ) submerged in water. What is the buoyant force on the solid coppor block in the water?
Due Dates > HW: Fluid Statics Resources Calculate the buoyant force on an object that has...
Due Dates > HW: Fluid Statics Resources Calculate the buoyant force on an object that has a volume of 0.400 m' and is immersed in seawater. The density of the seawater is 1030 kg/m 25200 N 412 N 2680 N 4040 N The apparent weight of an object while it is immersed in a fluid is the difference between its actual weight and the buoyani force. What is the apparent weight of the object if its mass is 705 kg?...
Consider a helium balloon with volume 2.15 L. a. Calculate the buoyant force on the balloon,...
Consider a helium balloon with volume 2.15 L. a. Calculate the buoyant force on the balloon, in newtons. Use 1.29 kg/m3 for the density of air. b. Given the mass of the rubber in the balloon is 1.65 g, what will be the net force, in newtons, in the vertical direction (taking up as positive) on the balloon if it is released? Neglect the volume of the rubber, and use 0.18×10-3 g/cm3 for the density of helium.
An object weighing 336 N in air is immersed in water after being tied to a...
An object weighing 336 N in air is immersed in water after being tied to a string connected to a balance. The scale now reads 256 N. Immersed in oil, the object appears to weigh 277 N. (a) Find the density of the object _______ kg/m3 (b) Find the density of the oil. ________kg/m3
3. Archimedes' Principle states that the buoyant force on an object partially or fully submerged in...
3. Archimedes' Principle states that the buoyant force on an object partially or fully submerged in a fluid is equal to the weight of the fluid that the object displaces. For an object of density po floating partly submerged in a fluid of density pf, the buoyant force is given by F P19 SA(y)dy, where g is the acceleration due to gravity and A(y) is the area of a typical cross-section of the object. The weight of the object is...
A large weather balloon whose mass is 222 kg is filled with helium gas until its...
A large weather balloon whose mass is 222 kg is filled with helium gas until its volume is 322 m3. Assume the density of air is 1.20 kg/m3 and the density of helium is 0.179 kg/m3. (a) Calculate the buoyant force acting on the balloon. 3786.72 N (b) Find the net force on the balloon. N upward (c) What additional mass can the balloon support in equilibrium? kg Please help!
buoyant force on aluminum (FB) is the buoyant force (Wo) is the weight of the block...
buoyant force on aluminum
(FB) is the buoyant force (Wo) is the weight of the block
outside of the fluid, (Wi) is the weight of the block inside of the
fluid.
Calculate what the value of the slope should be using your
values from the above table in Equation 1, should this graph be
liner ?
Equation is FB =
fluid x g x V
fluid (water) is 1,000 kg/m3
FB (N) v (m) W. (N) Wi(N) 0.005 132.3 83.3...
Due Dates > HW: Fluid Statics Resources Calculate the buoyant force on an object that has a volume of 0.400 m' and is immersed in seawater. The density of the seawater is 1030 kg/m 25200 N 412 N 2680 N 4040 N The apparent weight of an object while it is immersed in a fluid is the difference between its actual weight and the buoyani force. What is the apparent weight of the object if its mass is 705 kg?...
3. Archimedes' Principle states that the buoyant force on an object partially or fully submerged in a fluid is equal to the weight of the fluid that the object displaces. For an object of density po floating partly submerged in a fluid of density pf, the buoyant force is given by F P19 SA(y)dy, where g is the acceleration due to gravity and A(y) is the area of a typical cross-section of the object. The weight of the object is...
buoyant force on aluminum
(FB) is the buoyant force (Wo) is the weight of the block
outside of the fluid, (Wi) is the weight of the block inside of the
fluid.
Calculate what the value of the slope should be using your
values from the above table in Equation 1, should this graph be
liner ?
Equation is FB =
fluid x g x V
fluid (water) is 1,000 kg/m3
FB (N) v (m) W. (N) Wi(N) 0.005 132.3 83.3...
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