A circuit consists of a 292- resistor and a 0.206-H inductor. These two elements are connected in series across a generator that has a frequency of 93.6 Hz and a voltage of 251 V. (a) What is the current in the circuit? (b) Determine the phase angle between the current and the voltage of the generator. Note: The ac current and voltage are rms values and power is an average value unless indicated otherwise.
Solution)
Given,
resistor R = 292 Ω
inductor L = 0.206 H
frequency f = 93.6 Hz
voltage V = 251 V
(a) Impedance in the circuit
Z = √ R^2 +XL^2
= √ (292)^2 + (2πf L)^2
= √ [ (85264) + 14662.4
= 316.11 Ω
current I = V/Z = 251/ 316.11
= 0.794 A (Ans)
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(b) Phase angle
φ = tan^-1( XL/R)
= 22.52 deg (Ans)
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Good luck!:)
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