Question



Tea Calculate the approximate final temperature of water in a coffee cup calorimeter if 35:9 stor heat is added to 420.0 g of
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given:

Q = 33.9 KJ = 33900 J

m = 420 g

C = 4.184 J/g.oC

Ti = 22.6 oC

use:

Q = m*C*(Tf-Ti)

33900 = 420.0*4.184*(Tf-22.6)

Tf -22.6 = 19.29 oC

Tf = 41.89 oC

Answer: 41.89 oC

Add a comment
Know the answer?
Add Answer to:
Tea Calculate the approximate final temperature of water in a coffee cup calorimeter if 35:9 stor...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 5. Calculate the approximate final temperature of water in a coffee cup calorimeter if 33.9K heat...

    5. Calculate the approximate final temperature of water in a coffee cup calorimeter if 33.9K heat is added to 420.0 g of water initially at a temperature of 22.60 °C (the specific heat water is 4.184 J/g.K). 6. Determine the mass of a sample of water in a coffee cup calorimeter if the final temperature is 65.7 °C, the initial temperature is 22.3 °C, and 27.6 kJ of heat is added to the water specific heat of water is 4.184J/g•K).

  • PART A: A student constructs a coffee cup calorimeter and places 50.0 mL of water into...

    PART A: A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in calorimeter is determined to be 19.6 °C. To this is added 50.0 mL of water that was originally a temperature of 54.5 °C. A careful plot of the recorded temperature established T0 as 31.1 °C. What is the calorimeter constant (J/°C)? DensityH2O = 1.00 g/mL Specific HeatH2O = 4.184 J/g·°C PART...

  • A coffee-cup calorimeter has 44.1 g of water at 23.7 °C. A sample of copper weighing...

    A coffee-cup calorimeter has 44.1 g of water at 23.7 °C. A sample of copper weighing 12.7 g is heated in a boiling water bath to have an initial temperature of 100.0°C. The hot copper is then added to the water in the coffee-cup calorimeter. Given that the specific heat of solid copper is 0.385 J/(g·°C), calculate the final temperature of the water (and the copper) in the calorimeter.

  • < Question 9 of 10 ) A coffee cup calorimeter contains 161.10 g of water at...

    < Question 9 of 10 ) A coffee cup calorimeter contains 161.10 g of water at 24.05 °C. A 68.454 g piece of iron is heated to 95.44 °C. The piece of iron is added to the coffee cup caloriemter and the contents reach thermal equilibrium at 26.95 °C. The specific heat capacity of iron is 0.449 and the specific heat capacity of water is 4.184 How much heat, q, is lost by the piece of iron? Giron How much...

  • 3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it....

    3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in the calorimeter is determined to be 22.1 "C. To this is added 50.0 mL of water that was originally at a temperature of 54.5 C. A careful plot of the temperatures recorded after this established the temperature at T, was 31.86 °C. What is the calorimeter constant in J/C for this calorimeter?...

  • A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity = 4.184...

    A coffee cup calorimeter is prepared, containing 100.000 g of water (specific heat capacity = 4.184 J/g K) at initial temperature 80.000 C. A salt weighing 5.445 g is quickly added. The salt has a molar mass of 250.465 g/mol. The final temperature of the solution is 33.49 C. Assume no heat loss to the surroundings. Assume the specific heat capacity of the solution is equal to that of pure water, and that the mass of the solution is equal...

  • 3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it....

    3. A student constructs a coffee cup calorimeter and places 50.0 mL of water into it. After a brief period of stabilization, the temperature of the water in the calorimeter is determined to be 22.7 °C. To this is added 50.0 mL of water that was originally at a temperature of 54.5 C. A careful plot of the temperatures recorded after this established the temperature at To was 30.24 C. What is the calorimeter constant in J/C for this calorimeter?...

  • What will be the final temperature of the solution in a coffee cup calorimeter if a...

    What will be the final temperature of the solution in a coffee cup calorimeter if a 50.00 mL sample of 0.250 M HCl(aq) is added to a 50.00 mL sample of 0.250 NaOH(aq). The initial temperature is 19.50 C and the /\Hrxn is -57.2 kJ/mol NaOH. (assume the density of the solution is 1.00 g/mL and the specific heat of the solution is 4.18 J/g C).

  • In a coffee-cup calorimeter, 11.0-g sample of solid CaCℓ2 is dissolved in 125 g of water...

    In a coffee-cup calorimeter, 11.0-g sample of solid CaCℓ2 is dissolved in 125 g of water at 25.0 oC. The temperature in the calorimeter is measured to be 39.2 oC when the dissolution of CaCℓ2 is completed. Assuming that the specific heat of solution is equal to that of water, i.e., 4.184 J/g oC, calculate the heat of solution of CaCℓ2 in water, in kJ/mol. final answer is :-29.6

  • In the following experiment, a coffee-cup calorimeter containing 100 mL of H2O is used. The initial...

    In the following experiment, a coffee-cup calorimeter containing 100 mL of H2O is used. The initial temperature of the calorimeter is 23.0 ∘C. If 5.60 g of CaCl2 is added to the calorimeter, what will be the final temperature of the solution in the calorimeter? The heat of solution ΔHsoln of CaCl2 is −82.8 kJ/mol. Assume that the specific heat of the solution formed in the calorimeter is the same as that for pure water: Cs=4.184 J/g⋅∘C. Express your answer...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT