How many moles of Na₂S will be required to completely react with 40.0 mL of 0.200 M Fe(NO₃)₃? 3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq)

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How many moles of Na₂S will be required to completely react with 40.0 mL of 0.200 M Fe(NO₃)₃? 3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq)

How many moles of Na₂S will be required to completely react with 40.0 mL of 0.200 M Fe(NO₃)₃? 3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq) IMG_E2036[1].JPG

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Answer 1

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Answer #1

3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq)

number of moles of Fe(NO₃)₃ = 0.04 * 0.2 M = 0.008

0.008 moles Fe(NO₃)₃ reacts with = 0.008*3 / 2 = 0.012 moles Na₂S

answered by: dingding

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Answer 2

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How many moles of Na₂S will be required to completely react with 40.0 mL of 0.200 M Fe(NO₃)₃? 3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq)

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How many moles of Na₂S will be required to completely react with 40.0 mL of 0.200 M Fe(NO₃)₃? 3 Na₂S (aq) + 2 Fe(NO₃)₃ (aq) → Fe₂S₃ (s) + 6 NaNO₃ (aq)