Question

5) Refer to the following information for parts a-e: Sodium hydroxide solutions are common in chemical manufacturing, used in everything from the production of soaps to explosives. How could a chemist prepare 5.0 L of a 2.0 M aqueous stock solution of sodium hydroxide? b. Through dilution of the stock solution in Parta, how could a chemist prepare 250 mL of 0.5 M aqueous sodium hydroxide solution c. To safely dispose of solutions of strong bases like sodium hydroxide, it is necessary to first neutralize them by reaction with an acidic solution. Write and balance the molecular equation for the reaction of aqueous sodium hydroxide with aqueous sulfuric acid. d. What volume of a 0.5 M solution of sulfuric acid would be necessary to neutralize the 250 ml 0.5 M sodium hydroxide solution prepared in Part b. e. Write the net ionic equation for the reaction of sodium hydroxide with sulfuric acid in Part

Answer 1

A Prepacation SOL Caay NaoH Molar ma O NaoH = yo gImel Concentration (molacily)ight Molar mass Volume 2 M Mas ol NaoH 2 mat/L x40 9xSL Mass oNaoH mor Mass 400 NabH Ho04 NaoH Conintration oLsulhng holuint dissolvid in wul be 2M solution (b) Wle Molution rom Hallosing relation o freparation a dilub olution stock known conceatration Mdilute Vdilute Mstock Vstock 2 M Y Vstok= 0S M X250 mL Vstock OSM X2s0 mL 2M 62 S mL Vsto ck 6.2.S mL 2M stock then ailute it C250 mL-62-5mL) We have solution o NaDH to take Dnd upto 250mL 187 S mL byodding watir

(o 2NGOH Caa)tH2Soy Coa) la) from th neutralises above 2 meles more ok Hasou eauation Na oH Na oH= Millimolu O.5 M X 2SD mL 125 mmel 2 moles nutralise by Na oH mel H2soy 125 mmel NDOH neutri3es by mel H2Soy x125mmd Noot 2 mel NaoH 62:5 Mmeles HSO4 Concertration H,SOy Millimelus volume (mL) 62.S mme Volume 0 S M 62.5 mmet 125 mL Volume 0.5 M es to nutralise H2SO4 125 mL o OSM ntcusasy NaDH 2st Volume o H250y= 125 mL eTotal 1onic Eauation 2Na (a)+ 20 (a) + 2H (ay) +Soy Cay) 2Nat (a) So4 Cay) +2H0 Net ionic Equation 2Ht lay) + 20H (ay) 2H20R) 2- are spectator ons Na and S0
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