A light ray propagates in Material 1 with index of refraction ni = 1.17, strikes an...

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$A light ray propagates in Material 1 with index of refraction ni = 1.17, strikes an interface, then passes into Material 2 wi$

Answer 1

Answer #1

Here ,

n1 = 1.17

n2 = 1.49

let the angle of refraction is theta2

Using Snell's law

n1 * sin(theta1) = n2 * sin(theta2)

1.17 * sin(14.5 degree) = 1.49 * sin(theta2)

theta2 = 11.3 degree

the angle of refraction theta2 is 11.3 degree

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Answer 2

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