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A light ray propagates in a material with index of refraction 1.11, strikes an interface, and passes into a material whose in

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Answer #1

Using Snell's law:

1.11 x sin 40.7 = 1.47 x sin \theta

Sin\theta = (1.11/1.47) sin 40.7 = 0.492

So, \theta = 29.47 degrees

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