Question

Question: Starting with a 100,000 ug/mL manganese stock solution, write out a dilution scheme for the preparation 100mL each of 0.5, 1.0, and 2.0 mg/L calibration standards.

Note: My original scheme was to do the following, however this is not the most efficient scheme. The amount of stock solution that should be used is 50mL, not 100mL as shown in my calculation.

but noo'ol = 741 Gr cealal 1 (10,000 mg/L) (V.) = (0.1L) (100 mg) V, 0.4 (100 mgle) 10.000 mall = 0.001 me 100 NL) of stock sol. 2) (6.1L) (0.5 kg/h) = (100 mg/L)(V2) V = 0.12 (0.5 mgle) -0.00051 100 mill 50 ML dil. sol. (0.12) (1.0 mg)= (100 mg/L) (12) V-0.12(10mg/l) = 0.00 L 100 g/h 100 ny dil. sol. (0.1L) (2.0 ngh) = (100mg) (V)

Answer 1

starting concentration = 100,000 ug/mL - 100.000 1000 - 100 mg ima 100 % Vi = 100*0.5 Vi = 0.5 mL Volume of stock solution = 0.50mL 100 x V = 100 x 1.0 Vi= 1.00mL volume of stock = 1.00mL - 3) 100 X V = 100x 2.0 Vi = 2.00 volume of stock solution = 2.00mL