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Using R, program the following. Problem 1 (11.4) *The data set `carsafety` (**UsingR**) contains car-crash data....

Using R, program the following.

Problem 1 (11.4)
*The data set `carsafety` (**UsingR**) contains car-crash data. For several makes of car the number of drivers killed per million is recorded in 'Drivers.deaths'. The number of drivers of other cars killed in accidents with these cars, per million, is recorded in 'Other.deaths'. The variable 'type' is a factor indicating the type of car.*

*(a) Perform a one-way ANOVA of the model Driver.deaths~type. Is there a difference in population means? Did you assume equal variances? Normally distributed populations?*

*(b) Repeat with an ANOVA model of Other.deaths~type. Is there a difference in population means?*

math   Statistics-And-Probability   
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RStudio ile Edit Code viEW Plots Session Build Debug Protile loois Help Project: (None) anova.Rx data x Environment History Global Fminnnmrnt Namc Anova-test aov data Type Lergth Size 13 15.9 KB List of 13 Valic 15 16 17 #visual ising the data 18 plot.newO 19 mean value2<-aggregate (Other.deaths type,type, mean) 20 mean valuel 21 boxplot(Other .deaths-type,col-rainbow(4),x1ab=type.ylab=deaths, main-Boxplots data.fr... 4 5.1 KB 33 obs. of 4 varia. 1016 B 7 obs. of 2 variab. 1016 B 7 obs. of 2 variab. 1 KB List of 1 mean valuel data.fr... 2 2 mean value2 data.fr.... s1 of deaths type □ summary... 1 factor 33624 B Factor w/ 7 levels... vs type 23 var_test anova 3 832 B 2 obs. of 3 variab.. ] 25 26 27 Files Plots Packages Help Viewer mExport lop Level) Script Console chevrolet Malibu 1 large chevrolet Suburban 1 midsize :7 Mean79.55 Mean41.58 chevrolet Tahoe1 minivan 3rd Qu.: 94.00 3rd Q: 44.00 chevrolet venture pickup (other) Boxplots of deaths vs type :3 Median 74.00 Median 39.00 120 100 :2 Max. :161.00 Ma :128.00 27 subcompact:7 > plot.newO mean value2<-aggregate (other.deaths-type,type,mean) >mean valuel SUV 2 compact arge 4 midsize 5 minivan pickup 7 subcompact type Driver.deaths 69.71429 83.50000 73.33333 67.14286 39.66667 110.50000 110.42857 40 20 suv l arge mini sub > boxplot (other deaths-type, col-rainbon(4), x1 abstype,y1ab=deaths, ai n=Boxplots of deaths vs type,1 as-1, names-cC suv. com , 1 arge, mi d , min. pickup , sub), сех. 1 abel , 5 cex. axi s=1.5 ,cex. main-l. 5) O Type here to search rP ^ Dia ENG 11-02-2018RStudio ile Edit Code viEW Plots Session Build Debug Protile loois Help ⑧ Project: (None) nova.x data x Environment History or on Se Global Fmimnmrnt 33 plot.new) 34 qqnorm Cother.deaths) 35 library (car) 36 var-test1+1eveneTest (y-other deaths group=as. factor (type)) #checking the equality of variances 37 var_test1S Pr(oF) 0.05 this return ogical value false 38 39 40 41 Anova test<-aov Cother.deaths-type) 42 s2<-summary (Anova test) 43 s2 44 attributes (Anova test) 45 s2[[1] ]$.Pr(>F). >0.05 #this return the logical value FALSE so we reject the null hypothesis of equv 46 < 42:1 A Type Anova test aov Name Lergth Size 13 15.9 KB List of 13 Valic #checking the normality data.fr.... 4 mean valuel data.fr... 2 □ mean-value2 dat a. fr.. 2 summary... 1 data 5.1 KB 33 obs. of 4 varia. 1016 B 7 obs. of 2 variab 1016 B 7 obs. of 2 variab.. 1 KB List of 1 Wwe reject null hypotheis of equality of variance s1 □ type factor 33624 B Factor w/ 7 levels... 832 B 2 obs. of 3 variab.. ] var_test anova 3 Files Plots Packages Help Viewer lop Level) R Script Console-/ Normal Q-Q Plot -2 0 2 1ibrary (car) > var-testle-leveneTest (y#0ther.deaths,group=as.factor (type)) > var-test1$. Pr (-F).>0.05 #1his return logical value fal se 11 FALSE NA #checking the equality of variances Theoretical Quantiles 14 O Type here to search A a C ENG11-02-2018

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