Which is the correct answer: When you sum the torques on and object and set them...
Which is the correct answer: When you sum the torques on and object and set them equal to zero for an object in equilibrium, the axis about which the torques are calculated...
a) must be located at pivot
b) must be located at center of mass
c) should be located on an outer edge on the object
d) can be located anywhere
Homework Answers
If any object is in equilibrium,then net torque about any axis should be zero.Hence,axis can be located anywhere. So option (d) is correct.
Add Answer to:
Which is the correct answer: When you sum the
torques on and object and set them...
. If a disk rolls smoothly across a floor, what is the velocity of the point...
. If a disk rolls smoothly across a floor, what is the velocity of the point that is in contact with the floor? a) twice the velocity of the center of the disk b) equal to the velocity of the center of the disk c) zero 2. Stress is proportional to strain means that a) stress = constant x strain. b) stress (constant 1) X strain+ constant 2. stress Constant strain d) stress= constant 1 strain constant 2 e) Stress...
What is the moment of inertia of the object about an axis at the center of...
What is the moment of inertia of the object about an axis at the
center of mass of the object? (Note: the center of mass can be
calculated to be located at a point halfway between the center of
the sphere and the left edge of the sphere.)
If an object is in static equilibrium, there must be no net external torque: A) Group...
If an object is in static equilibrium, there must be no net external torque: A) Group of answer choices about an axis located at the edge of the object. B)about an axis located at the object's center of gravity. C)about an axis located beneath the object's center of gravity. D) about any axis.
An object is formed by attaching a uniform, thin rod with a mass of mr =...
An object is formed by attaching a uniform, thin rod with a mass of mr = 7.31 kg and length L = 5.68 m to a uniform sphere with mass ms = 36.55 kg and radius R = 1.42 m. Note ms = 5mr and L = 4R. *What is the moment of inertia of the object about an axis at the left end of the rod? *If the object is fixed at the left end of the rod, what...
This is, of course, a seesaw type object where the area of suport is moved. Post-Lab...
This is, of course, a seesaw type object where the area of
suport is moved.
Post-Lab Analysis Show algebraically that if the system is in equilibrium, the net torque will sum to zero about any point. Do this by designating an arbitrary point as a new axis of rotation, evaluating all torques about this new axis, and showing that the torques still sum to zero, provided they summed to zero around the old axis. For instance, let the point labeled...
Need help with part C. Thank you! This is the figure above. However, it has different...
Need help with part C. Thank you!
This is the figure above. However, it has different values than
the homework question above.
PRACTICE IT Use the worked example above to help you solve this problem. A woman of mass m = 53.6 kg sits on the left end of a seesaw-a plank of length L = 4.39 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes...
In a physics lab experiment for the determination of moment of inertia, a team weighs an...
In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 3.25 kg. They then hang the object on a pivot located 0.249 m from the object's center of mass and set it swinging at a small amplitude. As two of the team members carefully count 105 cycles of oscillation, the third member measures a duration of 269 s. What is the moment of inertia of the object with...
I need help with exercise and practice it. PRACTICE IT Use the worked example above to...
I need help with exercise and practice it.
PRACTICE IT Use the worked example above to help you solve this problem. m 56.3 kg sits on the left end of a seesaw A woman of mass -a plank of length L 4.68 m, pivoted in the middle as shown in the figure (a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 74.9 kg sit...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
Torques on a ruler
A ruler, balanced at its center point, has two coins placed on it, as shown in the figure. (Intro 1 figure) One coin, of mass M_1= 10g, is placed at the zero mark;the other, of unknown mass M_2, is placed at the 4.7 mark. The center of the ruler is at the 3.0 mark. The ruler is in equilibrium; it is perfectly balanced.[IMG]http://i40.tinypic.com/15cj2g9.jpg[/IMG]http://tinypic.com/view.php?pic=15cj2g9&s=5A)Does the pivot point (i.e., the triangle, in the diagram, upon which the ruler balances) exert a force...
. If a disk rolls smoothly across a floor, what is the velocity of the point that is in contact with the floor? a) twice the velocity of the center of the disk b) equal to the velocity of the center of the disk c) zero 2. Stress is proportional to strain means that a) stress = constant x strain. b) stress (constant 1) X strain+ constant 2. stress Constant strain d) stress= constant 1 strain constant 2 e) Stress...
What is the moment of inertia of the object about an axis at the
center of mass of the object? (Note: the center of mass can be
calculated to be located at a point halfway between the center of
the sphere and the left edge of the sphere.)
This is, of course, a seesaw type object where the area of
suport is moved.
Post-Lab Analysis Show algebraically that if the system is in equilibrium, the net torque will sum to zero about any point. Do this by designating an arbitrary point as a new axis of rotation, evaluating all torques about this new axis, and showing that the torques still sum to zero, provided they summed to zero around the old axis. For instance, let the point labeled...
Need help with part C. Thank you!
This is the figure above. However, it has different values than
the homework question above.
PRACTICE IT Use the worked example above to help you solve this problem. A woman of mass m = 53.6 kg sits on the left end of a seesaw-a plank of length L = 4.39 m, pivoted in the middle as shown in the figure. (a) First compute the torques on the seesaw about an axis that passes...
I need help with exercise and practice it.
PRACTICE IT Use the worked example above to help you solve this problem. m 56.3 kg sits on the left end of a seesaw A woman of mass -a plank of length L 4.68 m, pivoted in the middle as shown in the figure (a) First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 74.9 kg sit...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
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