Question

4. Why do ice cubes get smaller when left in the freezer for a long time?

  

Neither The ice cubes melt during the brief warming cycles of auto-defrost and freezer access, thus leaving the ice cubes smaller and making them stick together in clumps nor The water molecules of the ice sublime from the solid to gaseous phase without ever entering a liquid phase accurately explain why ice cubes get smaller in the freezer over time.

   

The ice cubes melt during the brief warming cycles of auto-defrost and freezer access, thus leaving the ice cubes smaller and making them stick together in clumps.

   

The water molecules of the ice sublime from the solid to gaseous phase without ever entering a liquid phase.

   

Both The ice cubes melt during the brief warming cycles of auto-defrost and freezer access, thus leaving the ice cubes smaller and making them stick together in clumps and The water molecules of the ice sublime from the solid to gaseous phase without ever entering a liquid phase occur.

5. What volume of 18.0 M sulfuric acid is required to prepare 26.20 L of 0.126 M H₂SO₄?

  

3.30 L

  

207.94 mL

  

0.183 L

  

471.60 mL

  

5.45 mL

Answer 1

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Solo: , 47. Ice cubes get smaller when left in the freezer for a long time because of the process of sublimation. Sublimation is the process of changing solid directly into gas. The water molecules on the surface of the ice join the water molecules in the air surrounding to it. Hence i option (clis corred. solid to The water gaseous phase molecules of the ice without ever entering sublime a liquid from the phase. 57. Criven : Molarity of sulphuric Acid - 18.0M let volume of 18.00 sulphuric Acid be xl. To prepare 26.20 of 0.126 M H₂ 504 . It is the question of dilution; 1418.0M, a roll 26.20L, 0.126M in case of Equivalent of H₂SO4 remains constant dilution, Equivalent = molarity X Nolume Xn-facton. Initial Equivalent = 18.0 x x X2 final Equivalent = 0.126 X 26.20 x2 Equating Initial = Final] option 18.0*2x x = 0.126 X 26.20x2 d = -0.1834 L 0.126 X 26.20 18-0 Honce; volume required = 0.183L

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