Question

Puntos:4 Th ck traveling along the +x direction is plotted in the figure 25 Evaluate the x-acceleration of the cart at time t-8.4 seconds 3.733 m/sA2 Correcto! Su recibo es 152-7431 Evaluate the x-acceleration at 15.7 seconds You will need to use graphical method to get the slope. Note: zero velocity is NOT on the bottom line 15.7 Envlar Respuesta Ya has introducido esa respuesta antes Unidades requeridas. Tries 1/10 Intentos Anteriores Evaluate the x-acceleration at 19.1 seconds You will need to use graphical method to get the slope. Note: zero velocity is NOT on the bottom line 6.0 ms2 Eviar Respuesta Ya has introducido esa respuesta Respuesta sin corregir. Use más Tries 2/10 antes Evaluate the distance the cart travels from 18.0 seconds to 20.0 seconds 4.400x101m iCorrecto! Su recibo es 152-9056

Answer 1

x acceleration from velocity time graph is determined by calculating the slope of the curve at that particular instant.

Acceleration at 15.7 (just after 15 seconds) = Slope at that instant

Velocity is constant, hence, slope is ZERO at 15.7 seconds

By formula,

$a_{15.7} = \frac{\Delta v}{\Delta t}$

$a_{15.7} = \frac{30-30}{18-15}$

$a_{15.7} = 0 m/s^{2}$

Slope at 19.1 seconds,

$a_{19.1} = \frac{\Delta v}{\Delta t}$

$a_{19.1} = \frac{15-30}{20-18}$

$a_{19.1} = -7.5 m/s^{2}$