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Average speed Puntos:4 The velocitv of a cart on a track traveling along the +x direction is plotted in the figure Evaluate the x-acceleration of the cart at time t-8.4 seconds. 3.733 m/sn2 Correcto! Su recibo es 152-7431Intentos Anteriores Evaluate the x-acceleration at 15.7 seconds. Enviar Resquesta Tries 0/10 Evaluate the x-acceleration at 19.1 seconds. Enviar Respuesta Tries 0/10 Evaluate the distance the cart travels from 18.0 seconds to 20.0 seconds. You will need to use graphical methods. Note: zero velocity is NOT on the bottom line 20 Enviar Respuesta Ya has introducido esa respuesta antes Unidades requeridas. Tries 2/10 Intentos Anteriores Enviar Mensaje de Discusión Enviar Reacción
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Answer #1

x acceleration at t = 15.7 sec is = 0 as we can see that velocity time graph is parallel to x axis at t = 15.7 sec

at t = 19.1 sec acceleration is equal to slope of linear graph that is = 15/2.5 = 6 m/s^2

distance travelled is equal to area under velocity time graph between t = 18 sec to 20 sec = 0.5 x 2 x (15+30) = 45 m

please rate it up thanks :)

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