EDTAEDTA is a hexaprotic system with the p?apKa values: p?a1=0.00pKa1=0.00, p?a2=1.50pKa2=1.50, p?a3=2.00pKa3=2.00, p?a4=2.69pKa4=2.69, p?a5=6.13pKa5=6.13, and p?a6=10.37pKa6=10.37. The distribution of the various protonated forms of EDTA will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTAEDTA, it is convenient to calculate the fraction of EDTAEDTA that is in the completely unprotonated form, Y4−Y4−. This fraction is designated ?Y4−αY4−. Calculate ?Y4−αY4− at two pH values pH=3.15 ?Y4−= pH=10.30 ?Y4−=
The expression - IF(A1 > 12, 6*A1, 2*A1) is used in a spreadsheet. Find the result if A1 is 7 Find the result if A1 is 13.
Show that A1, ..., An |=taut B iff |=taut A1 ->A2
->...->An -> B.
Show that A1, ,An-taut Biff는 B.
Show that A1, ,An-taut Biff는 B.
Calculate and draw impulse response for IIR filters: I a) a1 =0,5; b)a1 =0,8; c) a1 =0,8; a2 =-0,6 II a) a1 =0,6; b)a1 =0,9; c) a1 =0,6; a2 =-0,5
Use mathematical induction to show that P(A1∩A2∩...∩An) = P(A1)P(A2|A1)P(A3|A1∩A2)....P(An|A1∩A2∩...∩ An-1) You can assume that you know P(A|B) = P(A|B)P(B)
me Remaining: 22:22:48 Hide/Show Time Remaining Part 1 of 1 - Question 4 of 40 =IF(A1=1;A1:A1;IF(A1=10;2A1:3*A1)) If cell A1 equals 10, the function returns O A. 1 OB. 10 OC. 20 D. -10 Reset Selection Previous Next Save Gateway Mobile View The Sakal Project 2011 Tüm haklan saklıdır. Istanbul Kültür Universitesi CATS - CATS - Sakai 10.5 (Kernel 10.5) - Server saka Appliku.edu.tr
There is a probability in cell A1. =NORMSINV(A1) returns the value z, what will this formula return? =NORMSINV(1-A1)
The prior probabilities for events A1 and A2 are P(A1) = 0.30 and P(A2) = 0.40. It is also known that P(A1 ∩ A2) = 0. Suppose P(B | A1) = 0.20 and P(B | A2) = 0.05. If needed, round your answers to three decimal digits. (a) Are A1 and A2 mutually exclusive? Explain your answer. The input in the box below will not be graded, but may be reviewed and considered by your instructor. (b) Compute P(A1 ∩...
6) (10 points) The prior probabilities for events A1 and A2 are P(A1) = 0.40 and P(A2) = 0.60. It is also known that P(A1 or A2) = 1. Suppose P(BA1) = 20 and P(B|A2) =0.05. a. Are A1 and A2 mutually exclusive? Explain. (2 point) b. What is the probability that A1 does not occur? (2 point) C. Compute P(A2 and B) if A1 and B are independent (3 points) d. Compute P(A1 and B) (3 points)
The prior probabilities for events A1 and A2 are P(A1) = 0.45 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(B | A1) = 0.20 and P(B | A2) = 0.05. If needed, round your answers to three decimal digits. a) Are A1 and A2 mutually exclusive? b) Compute P(A1 ∩ B) and P(A2 ∩ B). c) Compute P(B). d) Apply Bayes’ theorem to compute P(A1 | B) and P(A2 | B).