Question

48 students participated in evaluating small package of skittles. The following table shows the result of this study. AssumeQuestion 2) Construct a 95% 2-sided confidence interval on the mean weight of the skittles.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

the weight of skittles is normally distributed with a standard deviation 0 = 2

Sample Mean X = Population Standard Deviation (0) = Sample Size (N) =

The critical value for a = 0.05 is ze = 21-0/2 = 1.96. The corresponding confidence interval is computed as shown below: C1 =

The 95%, 2-sided confidence interval on the mean weight of the skittles is (61.48,62.62) grams

Add a comment
Know the answer?
Add Answer to:
Question 2) Construct a 95% 2-sided confidence interval on the mean weight of the skittles. 48...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 7) Construct a 95% 1-sided lower limit confidence interval on the percentage of green skittles....

    Question 7) Construct a 95% 1-sided lower limit confidence interval on the percentage of green skittles. (α=0.05) Please write legibly. Will rate and comment. Thank you. 48 students participated in evaluating small package of skittles. The following table shows the result of this study. Assume the weight of skittles are normally distributed with standard deviation of 2 grams. Net Weight Green Red Yellow Brown Orange Count 2923 Total 2978.4 576 589 641 531 586 Sample Mean 62.05

  • Question 6) Company claims that more than 19% skittles are green. Do you agree with this...

    Question 6) Company claims that more than 19% skittles are green. Do you agree with this claim? Use α=0.05. Will rate and comment. Thank you. 48 students participated in evaluating small package of skittles. The following table shows the result of this study. Assume the weight of skittles are normally distributed with standard deviation of 2 grams. Net Weight Green Red Yellow Brown Orange Count 2923 Total 2978.4 576 589 641 531 586 Sample Mean 62.05

  • Question 5) Does standard deviation weight differ from 2 grams if the standard deviation of the...

    Question 5) Does standard deviation weight differ from 2 grams if the standard deviation of the sample is 2.067 grams (α=0.05)? Will rate and comment. Thank you. 48 students participated in evaluating small package of skittles. The following table shows the result of this study. Assume the weight of skittles are normally distributed with standard deviation of 2 grams. Net Weight Green Red Yellow Brown Orange Count 2923 Total 2978.4 576 589 641 531 586 Sample Mean 62.05

  • Question 1) Company claims that packages of skittle contain 61.5 grams of skittles. Do you agree...

    Question 1) Company claims that packages of skittle contain 61.5 grams of skittles. Do you agree with this claim? use α = 0.05. Question 3) Consider question 1. Find the power of test for the case in which the true mean weight of skittles is 62.5 gram. Question 4) Consider question 3. What sample size would be required to detect a true mean weight of 62.5 if you wanted the power of test to be at least 0.99? Please write...

  • Calculate the mean, median, and standard deviation for the total number of candies (per bag). Construct...

    Calculate the mean, median, and standard deviation for the total number of candies (per bag). Construct a histogram of the total number of candies (per bag). Use the z-score method to identify any potential outliers and outliers. Assume the total number of candies is normally distributed, calculate the probability that a randomly sampled bag has at least 55 candies in a bag. If a random sample of 50 bags is selected, find the probability that the mean number of candies...

  • Which of the following is a characteristic of a binomial probability experiment

    7. Which of the following is a characteristic of a binomial probability experiment? A. Each trial has at least two possible outcomes B. P(success) = 1 – P(failure) C. The binomial random variable x is the count of the number of trials that occur D. The result of one trial affects the probability of success on any other trial Answer: 8. If the random variable z is the standard normal score, which of the following probabilities could easily be determined...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT