Question

Question 3 In Figure a particles 1 and 2 have charge 29.0 μC each and are held at separation distance d 3.80 m a) what the magnitude o heeectrostati orce on particle 1 due to particle 2? In Figure b particle 3 of charge 29.0 C is positioned so as to complete an e u tera triangle b what S i e magnitude i tenet electrostatic force on particle 1 due to particles 2 and 3? 2 (a) Number Units (b) Number Units

Answer 1

Magnitude of electrostatic force due to a charge q_1 on another charge q_2 is given by, Coulomb's Law, F = 1/4 pi epsilon_0 q_1 q_2/r^2 (a) q_1 = 29.0 mu C = 29.0 times 10^-6 C = q_2 = 29.0 times 10^-6 C. Therefore F = 1/4 pi epsilon_0 q_1 q_2/d_2 = 9 times 10^9 times (29 times 10^-6) times (29 times 10^-6)/(3.8)^2 N = 0.524 N This's Force on partied 1 due to 2 or on particle 2 due to 1. (b) Particles 1,2 and 3 are such that, they are on vertices of an equilateral triangle. Force on particle 1 due to particle 2. F_12 = 1/4 pi epsilon_0 q_1 q_2/d_2 = 0.524 N from part (a). Force on particle 1 due to particle 3 is, F_13 = 1/4 pi epsilon_0 q_1 q_2/d_2 \r\n Because q_3 = 29 mu C = 29 times 10^-6 C F_13 = 9 times 10^9 times (29 times 10^-6) times (29 times 10^-6)/(3.8)^2 0.524 N.