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40. The position of a particle in meters is given by x 2.5t+ 3, where tis the time in seconds. What are the 3.1-45, where tis the time in seconds. Wh instantaneous velocity and instantaneous acceleration at /- 0.0 s? Att 2.0 s? What are the average velocity and average acceleration for the time interval 0 sts 2.0 s
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Answer #1

Solving the problem by using the basic definitions of instantaneous velocity & acceleration and average acceleration and velocity.

Question (40) > given equation ot mohon parhle., unw defnihon , enstant aneow veloeh ot an^ Usin equahon 0 Ve 2.st t 3-1ё-Y.st3) : 2.5 t 2x3l t- y.SX3t2 d d t Aico, by definihon, instantaneous acceleration Дгипу Qt- 6.2- 27t fom equaban (we can see that the acelerahen of the parhde changes with hme, so ct is not canttant nd e all the equahons f mo ban art applr cable ony for constant actelerahon Hen a, equahons of mo hon cannol be Used to solve the >roblemcalcu lah m equahun (i m eauahon ( ao: 6.2mstantaneous acceler aboi at to o Calcula h ng Ves at at t=2.0s - 13-S (2)3i -ve san shs us that the drechon。 a12-41.8 mfu |-> instantaneous accelerahon at t=20s ngahvc accelerahon or decceterdh。srhon at 2 shon at duspla camen t hme taken -186-0 3 ms yay: -9.3 m, → average velo u average accele rahon Cuv by definihen, average acuele rahonaav Chang in velou lime taken 2

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