Solution) L = 25 mH = 25×10^(-3) H
Vrms = 150 V
(a) f = 60 Hz
Inductive reactance , XL = ?
XL = wL = (2(pi)f)L
XL = (2(pi)60)25×10^(-3)
XL = 9.42 ohms
Rms current , Irms = ?
Irms = (Vrms/XL)
Irms = (150)/(9.42)
Irms = 15.9 A
(b) f = 6 KHz = 6×10^(3) Hz
XL = (2(pi)f)L
XL = (2(pi)×6×10^(3))(25×10^(-3))
XL = 942.47 ohms
Irms = (Vrms)/(XL)
Irms = (150)/(942.47)
Irms = 0.159 A
So rms current decreases .
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