The value of Δ?°′ for the conversion of 3-phosphoglycerate to 2-phosphoglycerate (2PG) is +4.40 kJ/mol . If the concentration of 3-phosphoglycerate at equilibrium is 2.45 mM , what is the concentration of 2-phosphoglycerate? Assume a temperature of 25.0°C .
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The value of Δ?°′ for the conversion of 3-phosphoglycerate to 2-phosphoglycerate (2PG) is +4.40 kJ/mol ....
The value of Δ G ° ' for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is + 7.53 kJ/mol . If the concentration of dihydroxyacetone phosphate at equilibrium is 2.45 mM , what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0 ° C . [GAP] = mM
In glycolysis, the enzyme phosphoglycerate mutase converts 3-phosphoglycerate (3PG) to 2- phosphoglycerate (2PG). a. The standard free energy change for this reaction at 37°C is +4.4 kJ/mol. Calculate the equilibrium constant. Type out all your work and underline the final answer. You will only receive credit for work that is shown. b. Referring back to part a, if the concentration of 3PG at equilibrium for the reaction is 15.2 mm, calculate the equilibrium concentration of 2PG. Type out all your...
Enolase converts 2-phosphoglycerate (2PG) to phosphoenolpyruvate (PEP). This reaction has a ΔG’o= + 7.5 kJ/mol, but the reaction occurs readily under normal cellular conditions. What is the ratio of [PEP]/[2PG] at equilibrium, at 25oC? In this case, If 2PG is present within the cell cytosol at a concentration of 6 x 10-3M and the concentration of PEP = 0.10 x 10-3M, what is the ΔG of the reaction at 37oC?
The value of ΔG°\' for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is 7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.65 mM, what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0 °C. The constant R = 8.3145 J/(mol·K) [GAP] = ??? mM
The value of ΔG°\' for the conversion of dihydroxyacetone
phosphate to glyceraldehyde-3-phosphate (GAP) is 7.53 kJ/mol. If
the concentration of dihydroxyacetone phosphate at equilibrium is
2.85 mM, what is the concentration of glyceraldehyde-3-phosphate?
Assume a temperature of 25.0 °C. The constant R = 8.3145
J/(mol·K)
Map do Sapling Learning macmilan learning The value of AG° for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is +7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.85 mM, what is...
CH6Q17 The value of ΔG°'ΔG°′ for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is +7.53 kJ/mol+7.53 kJ/mol. If the concentration of dihydroxyacetone phosphate at equilibrium is 2.25 mM2.25 mM, what is the concentration of glyceraldehyde-3-phosphate? Assume a temperature of 25.0°C25.0°C. [GAP]= _________ mM
emates 3 Homework Bioenergetics Biochemical reactions Resources Hint The value of AG® for the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) is +1.67 kJ/mol. If the concentration of glucose-6-phosphate at equilibrium is 2.55 mm, what is the concentration of fructose-6-phosphate? Assume a temperature of 25.0°C. [F6P] = mM
4. The conversion of citrate to isocitrate was found to have a AG" of 6.4 kJ/mol under standard state conditions. In a liver cell, the concentration of citrate was measured to be 0.526 mM and the concentration of isocitrate was 0.0112 mM. The temperature was 25 °C. (Show work for full credit.) Is this reaction at equilibrium in the cell? To calculate this, first: i) Calculate Q for this reaction in the cell. ii) Calculate Keq for this reaction. Calculate...
The standard change in Gibbs free energy is Δ?°′=7.53 kJ/mol .
Calculate Δ? for this reaction at 298 K when [dihydroxyacetone
phosphate]=0.100 M and [glyceraldehyde-3-phosphate]=0.00600 M .
Thank you!
For the aqueous reaction CH2OH Н— —он SO CH-0–_0 CH -0 - 0- dihydroxyacetone phosphate = glyceraldehyde-3-phosphate the standard change in Gibbs free energy is AGⓇ' = 7.53 kJ/mol. Calculate AG for this reaction at 298 K when [dihydroxyacetone phosphate) = 0.100 M and [glyceraldehyde-3-phosphate] = 0.00600 M AG = kJ/mol
the value on top is -2.1kj/mol
2.1 kJ/mol. The following reaction has a value of AGⓇ = CH3Br + H2S CH,SH HBr a) Calculate key at room temperature (25°C) for this reaction as written. b) Starting with 1 M solution each of CH3Br and H2S, calculate the final concentration of all four species at equilibrium. Please be thorough in your presentation AGⓇ = -2.303RT(log kea); at 25°C, RT= 2478 J/mol or 2.48 kJ/mol