Homework Answers
1. Just simply multiply M x mL = mmol
2. Na2CO3 (aq) + CaCl2 (aq) --> CaCO3 (s) + 2NaCl (aq) is the balanced equation for the reaction.
3. 1 mmol Na2CO3 reacts with 1 mmol CaCl2 according to above equation.
4. If both have same number of moles then they will react completely.
5. If any reactant has lower number of mmol then we say it as limiting reactant, in such case same number of other reactant mmol are used up and remaining will remain unused and we will mention it as excess reactant.
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Analysis 1. Complete the following table (1 mmol = 103 mol) Na CO, in 5 mL...
Theoretical Yield Caco, in mmol Excess CO2-in mmol Excess Cain 1. Complete the following table (I...
Theoretical Yield Caco, in mmol Excess CO2-in mmol Excess Cain 1. Complete the following table (I mmol - 10 mol) Concentration of Na,Co, in 5 mL Caci, in 5 mL Tube of Solution in of Solution in Na.co, CaCl, mmol mmol 1 1.0 M 10M 1.0M 0.5 M 3 0.5 M 0.5 M 4 0.5 M 1.0M 5 0.5 M 0.1 M 6 0.5 M 0.01 M L a d in each test tube agree with the calculated theoretical
Paragraph Styles CARBONATE Data Sheet Table 5. Mass Data Item Mass (g) Calcium Chloride (CaCl)
1. Using the mass and molar mass of \(\mathrm{CaCl}_{2}\) determine the number of moles of \(\mathrm{CaCl}_{2}\).2. Convert the moles of \(\mathrm{CaCl}_{2}\) to moles of \(\mathrm{CaCO}_{3}\) using a mole ratio.3. Convert the moles of \(\mathrm{CaCO}_{3}\) to grams of \(\mathrm{CaCO}_{3}\) using the molar mass.4. Using the mass of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) determine the number of moles of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\).5. Convert the moles of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) to moles of \(\mathrm{CaCO}_{3}\) using a mole ratio.6. Convert the moles of \(\mathrm{CaCO}_{3}\) to grams of \(\mathrm{CaCO}_{3}\) using...
5. Fill in the following table to show amounts to use and theoretical yield. Product Epoxide...
5. Fill in the following table to show amounts to use and theoretical yield. Product Epoxide product Moles MW Density Amount Amounts Reactant Reactant MCPBA Product from last experiment 22 mmol 22 mmol 172.57 g/mol 82.14 g/mol NA 0.83 g/ml Calculate and Calculate and write write in pre-lab in pre-lab notes notes 22 mmol 98.14 g/mol NA This amount will be your theoretical yield.
using the procedure above complete the stoichiometry table Procedure In an oven-dried, 100 ml round bottom...
using the procedure above complete the stoichiometry
table
Procedure In an oven-dried, 100 ml round bottom flask containing magnetic stirring bar was added hydrobenzoin (1.0 8.4.7 mmol), anhydrous iron(III) chloride (0.3 g, 1.8 mmol), and anhydrous acetone (30 ml). The mixture was heated to reflux and stirred for 30 min. The reaction mixture was cooled tort and transferred to a separatory funnel containing 10% aq potassium carbonate (10 mL). Water (50 mL) was added and the aqueous solution was extracted...
Cle Reaction equation (KMnO4 reaction): Reagent Table Chemical cyclohexene FW mp (℃) | bp ec) |...
Cle Reaction equation (KMnO4 reaction): Reagent Table Chemical cyclohexene FW mp (℃) | bp ec) | mmol | mass (g)| density | volume | mmol | mass (g) | (g/mL)1 °C) (g/mol) (mL) 0.311 0.85 N/A 158.031 NIA | 31.9111 N/A I NA I NA NA İ NA 14.0 | NA NA sodium hydroxide (0.1 M) tert-butyl alcohol ethyl acetate TA. 111 N/A 1120,8 l N/A | N/A | N/A | N/A 155.111 N/A | N/A | NA NA I...
1. Complete the following table: (Hint-Keep track of your units) equivalents mmol density mL Compound sulfuric...
1. Complete the following table: (Hint-Keep track of your units) equivalents mmol density mL Compound sulfuric acid (18M) MW XXX XXX XXX 0.840 2.96 1.04 0.302 benzaldehyde sulfuric acid (18M) nitric acid (15.9M) XXX XXX XXX 0.280 XXX XXX XXX 0.372 2. What is the theoretical yield for this reaction (nitration of benzaldehyde)?
I just need help understanding the steps to get the theoretical yeild and percent yield of...
I just need help understanding the steps to get the
theoretical yeild and percent yield of CaCO3. using the given
information.
H.Y. & S. D. Precipitating Calcium Carbonate CHMI21 General Chemistry Lab 1 • Treatment of Data: 14) mole amount of Na CO, 15) mole amount of CaCl 16) limiting reagent .00832 00976 NonCO₃ .00735 .832 .au 112.98 mole amount of CaCO, 17) 18) 19) 20) Theoretical Yield (g) of Cacos Actual Yield (g) of Caco, Percent Yield (%) Calculations...
Suppose that the following data are obtained for an enzyme-catalyzed reaction: [S] (mM) V (mmol ml-1min-1)...
Suppose that the following data are obtained for an enzyme-catalyzed reaction: [S] (mM) V (mmol ml-1min-1) 0.1 3.33 0.2 5.00 0.5 7.14 0.8 8.0 1.0 8.33 2.0 9.09 a.) From a double-reciprocal plot of the data, determine Km and Vmax. b.) Assuming that the enzyme present in the system had a concentration of 10-6 M, calculate its turnover number.
what is the equivalent for each reactants and complete the result table please! Synthesis of 13-(4-methylphenyl)...
what is the equivalent for each reactants and complete the result
table please!
Synthesis of 13-(4-methylphenyl) isoxazole-5-yl) methanol Compounds MW(g/mol) mmol Équivalent Mass (g or mL) 0.16ml 10ml 1.15 Triethylamine chloroform Pro-2-yn-ol 4- methylbenzaldehyde Density (g/cm ) 0.726 1.492 0.904 1.019 101.19 119.38 132.16 120.15 1 ml 16,9 1.15 g 11.1 Result table 2 MW(g/mol) Theoretical results (mmol) Theoretical Experimental Pourcentage Résult (mg) result (en mg ou g) 1.0251g Produit 187.19 Percent yield = actual yield theoretical yield = 3...
Prelab Questions. Complete the following table: (hint keep track of your units) MW equivalents mmol ml...
Prelab Questions. Complete the following table: (hint keep track of your units) MW equivalents mmol ml density XXX 0.920 XXX XXX Compound sulfuric acid (18M) methyl benzoate sulfuric acid 1.088 0.440 XXX XXX XXX 0.460 (18M) XXX 0.440 XXX XXX nitric acid (15.9M) 2. What is the theoretical yield for this reaction? 3. Why is an ice bath employed in the nitration of methyl benzoate? (hint: look at the energy diagram shown on pg 1 of the experiment)
Theoretical Yield Caco, in mmol Excess CO2-in mmol Excess Cain 1. Complete the following table (I mmol - 10 mol) Concentration of Na,Co, in 5 mL Caci, in 5 mL Tube of Solution in of Solution in Na.co, CaCl, mmol mmol 1 1.0 M 10M 1.0M 0.5 M 3 0.5 M 0.5 M 4 0.5 M 1.0M 5 0.5 M 0.1 M 6 0.5 M 0.01 M L a d in each test tube agree with the calculated theoretical
1. Using the mass and molar mass of \(\mathrm{CaCl}_{2}\) determine the number of moles of \(\mathrm{CaCl}_{2}\).2. Convert the moles of \(\mathrm{CaCl}_{2}\) to moles of \(\mathrm{CaCO}_{3}\) using a mole ratio.3. Convert the moles of \(\mathrm{CaCO}_{3}\) to grams of \(\mathrm{CaCO}_{3}\) using the molar mass.4. Using the mass of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) determine the number of moles of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\).5. Convert the moles of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) to moles of \(\mathrm{CaCO}_{3}\) using a mole ratio.6. Convert the moles of \(\mathrm{CaCO}_{3}\) to grams of \(\mathrm{CaCO}_{3}\) using...
5. Fill in the following table to show amounts to use and theoretical yield. Product Epoxide product Moles MW Density Amount Amounts Reactant Reactant MCPBA Product from last experiment 22 mmol 22 mmol 172.57 g/mol 82.14 g/mol NA 0.83 g/ml Calculate and Calculate and write write in pre-lab in pre-lab notes notes 22 mmol 98.14 g/mol NA This amount will be your theoretical yield.
using the procedure above complete the stoichiometry
table
Procedure In an oven-dried, 100 ml round bottom flask containing magnetic stirring bar was added hydrobenzoin (1.0 8.4.7 mmol), anhydrous iron(III) chloride (0.3 g, 1.8 mmol), and anhydrous acetone (30 ml). The mixture was heated to reflux and stirred for 30 min. The reaction mixture was cooled tort and transferred to a separatory funnel containing 10% aq potassium carbonate (10 mL). Water (50 mL) was added and the aqueous solution was extracted...
Cle Reaction equation (KMnO4 reaction): Reagent Table Chemical cyclohexene FW mp (℃) | bp ec) | mmol | mass (g)| density | volume | mmol | mass (g) | (g/mL)1 °C) (g/mol) (mL) 0.311 0.85 N/A 158.031 NIA | 31.9111 N/A I NA I NA NA İ NA 14.0 | NA NA sodium hydroxide (0.1 M) tert-butyl alcohol ethyl acetate TA. 111 N/A 1120,8 l N/A | N/A | N/A | N/A 155.111 N/A | N/A | NA NA I...
1. Complete the following table: (Hint-Keep track of your units) equivalents mmol density mL Compound sulfuric acid (18M) MW XXX XXX XXX 0.840 2.96 1.04 0.302 benzaldehyde sulfuric acid (18M) nitric acid (15.9M) XXX XXX XXX 0.280 XXX XXX XXX 0.372 2. What is the theoretical yield for this reaction (nitration of benzaldehyde)?
I just need help understanding the steps to get the
theoretical yeild and percent yield of CaCO3. using the given
information.
H.Y. & S. D. Precipitating Calcium Carbonate CHMI21 General Chemistry Lab 1 • Treatment of Data: 14) mole amount of Na CO, 15) mole amount of CaCl 16) limiting reagent .00832 00976 NonCO₃ .00735 .832 .au 112.98 mole amount of CaCO, 17) 18) 19) 20) Theoretical Yield (g) of Cacos Actual Yield (g) of Caco, Percent Yield (%) Calculations...
what is the equivalent for each reactants and complete the result
table please!
Synthesis of 13-(4-methylphenyl) isoxazole-5-yl) methanol Compounds MW(g/mol) mmol Équivalent Mass (g or mL) 0.16ml 10ml 1.15 Triethylamine chloroform Pro-2-yn-ol 4- methylbenzaldehyde Density (g/cm ) 0.726 1.492 0.904 1.019 101.19 119.38 132.16 120.15 1 ml 16,9 1.15 g 11.1 Result table 2 MW(g/mol) Theoretical results (mmol) Theoretical Experimental Pourcentage Résult (mg) result (en mg ou g) 1.0251g Produit 187.19 Percent yield = actual yield theoretical yield = 3...
Prelab Questions. Complete the following table: (hint keep track of your units) MW equivalents mmol ml density XXX 0.920 XXX XXX Compound sulfuric acid (18M) methyl benzoate sulfuric acid 1.088 0.440 XXX XXX XXX 0.460 (18M) XXX 0.440 XXX XXX nitric acid (15.9M) 2. What is the theoretical yield for this reaction? 3. Why is an ice bath employed in the nitration of methyl benzoate? (hint: look at the energy diagram shown on pg 1 of the experiment)
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