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Cle Reaction equation (KMnO4 reaction): Reagent Table Chemical cyclohexene FW mp (℃) | bp ec) | mmol | mass (g)| density | volume | mmol | mass (g) | (g/mL)1 °C) (g/mol) (mL) 0.311 0.85 N/A 158.031 NIA | 31.9111 N/A I NA I NA NA İ NA 14.0 | NA NA sodium hydroxide (0.1 M) tert-butyl alcohol ethyl acetate TA. 111 N/A 1120,8 l N/A | N/A | N/A | N/A 155.111 N/A | N/A | NA NA I NA I 2.0 15 NANA NA NA Note: For those reagents that are in solution, the FW, mmol, and mass columns refer to the solute in the solution Limiting reagent for potassium permanganate reaction: Theoretical yield for potassium permanganate reaction: 101
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The relationship between mass and volumet s Mass = Volume × Density Calculate the mass of cyclohexeneisas follows Mass-Volume x Density 0.05mLx0.811g/ mL 0.041 g Calculate the molof cyclohexene is as follows :0.041 g C6H12× 32 14 gCsH Calculate the monol of cyclonexene is as follows: 4.94x10 mol C,H ב-- 0.494mmol CsHn 10* mol 1mol KMnO lmmol 158.03g KMnO, 10mol Calculate the mmol of KMnO4 is as follows : 0.1 g KMnO.Χ The reaction between KiMnO, and cyclohexene is as follows C6H12 ta-C6H ב (OH)2(cyclohexane-1,2-diol) Calculate the moles C,H12(OH)2 produces for 0.494mmol CH12 as follows 0.633mmol KMnO, M?2O lmolCH2 6-12 Calculate the molesCsH^(OH)2 produces or0.633mmol KMnO, as follows 0.633mmol Kdo,1mol CoHO2 Therefore, limiting reagentis CH becauseitlimits the product Calculate the theoretical yield asfollows 0.494x 10%no/C6H12 (OH), X Therefore,theoreti cal yield for this reaction is 5.74x102 g CH (OH) mol KMnO, 116.15g CjH (OH2 lmol CH (OH)2

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