Question

A sealed room has a volume of 32 m3. It's filled with air, which may be assumed to be diatomic, at a temperature of 25°C and a pressure of 9.95 ✕ 104 Pa. A 1.14 kg block of ice at its melting point is placed in the room. Assume the walls of the room transfer no heat. What is the equilibrium temperature (in °C)?

Answer 1

Soluhen Given Sealed room volume 2 3.2 m3 diatomic Tempur - 259 pressure = 9.950 1.4 Pa m2 1.1419 block oc Temprature in equilibrium od Trice a mosstce a 1.14 kg. block latent Heat Ice = L = 3348103 J1 kg Specific babout Heat water z cija 41865 Tiaire 250 Piaira 9.988 104 Pa. R2 8.31 J/molk » Heat loss and gain equilibrium Blosst @gain =0 dairt Ssce=0 & air 2 ncrot a see mil ① Subtituting value ean NNOT + Mia Lice no

I using Ideal Ceas equation pvz NRT pv n 2 RT Heat Saira - 25 nov 2- 25 pv cu RT gice a mice LF I sice & 1.148 3348103 ) 3.80X105) Saira – 250 q qS X 104 x 32. Sé 6.6 273+25) - 66.778 104 2 – 6.6778105 J Saira

equation o replace Temprature 258 Saira - Sice sair o Tair Piv 512 Tiair - dice a stair (P. V . Siz Tsair - Traira - Bice 2T air 5Piv Tfaire tair - dice 2 Tair 5Piv D (25+213) - 3.857105 x 2x(25+273) SX9.95X10Y X 32 fairz 298- 14.41 Tfair a 283.50k Traira 283.88-273 = . 10.58% Transa 10.58% equation again final Tomb dair & & water = 0 stair LP.V ).stmwcwotw zo Tiair Now 2 Tt2 Trair / SPV 12 Tair +mw ew Tiw Spix tmuw 2Tiarr

- sx 9.95% 101428 mw Cw Tiw Itz C 273+ 10.58) + 2x 298 sx 9.95 X107 x 257 mwcw. 2x290 2 283.58t 20868.28 + 1.1484186 X 273 20668.2 stl.ly X 4186 Tr 20 31.6k 15116