Question

A: The normality of an aqueous solution of hydrochloric acid is determined by titration with a 0.161 N sodium hydroxide solution If 26.6 mL of sodium hydroxide are required to neutralize 14.2 mL of the acid, what is the normality of the hydrochloric acid solution?__N

B: The normality of an aqueous solution of hydroiodic acid is determined by titration with a 6.19×10-2 N barium hydroxide solution. If 38.3 mL of barium hydroxide are required to neutralize 19.6 mL of the acid, what is the normality of the hydroiodic acid solution? __N

Answer 1

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Here the answer is

(A) Ale to Law of Equivalence NV = N2V 2 N = Normality of NaoH = 0.161 V : vol. of NaOH used = 26.6 ml N₂ = Normality of Hol to be calculated V₂ = Vol. of Hic used = 14.2 ml Applying above formula 161 x 26,6 = N2 x 14.2 Nz = 5161 X 26.6 14,2 302 N 16) (N. V.) NV2) ner 619x1024 38.3 = Nuci x 19,6 NAG = .121 N