Question

Question 2 The data below was obtained from experiments using an inhibitor of an enzyme which exhibits mixed type inhibition. Use the data to determine Km Vmax, Ki and aki. Your answer should include tabulated transformations of the data, the graphs used to obtain kinetics values and a brief narrative explaining how you arrived at your answers e.g. The X intercept represents value-1/A and hence A is equal to..... [S] 0.3 0.6 0.9 1.2 1.6 2 V+0.1mMv+0.3mM DD 182.14 134.21 87.93 300.00 225.66 150.89 382.50 291.98 198.19 443.48 342.28 235.02 503.70 393.06 273.09 548.39431.47 302.49 V+0.5mm 0 65.38 113.33 150.00 178.95 209.23 232.88 Units: (S) is in mM, v is in micromoles/min/mg

Can someone help. I'm desperate. I just need to know how I should go about this question what equations would I need to make the graphs? what graphs need to be made? and how to explain the process.
I know it's a long question. But please help it's a huge chunk of my marks. It would be greatly appreciated. Thank you

Please help I need to know the process and what graphs need to be made and what I need to input

Answer 1

From the enzyme catalyst aqua relation. We have z B K CE.] cs.] kz=rate coust. [s.] tkm [6.] concentration - of enzyme = man [s.] so= cone of [s]+ km substrate Ku - Michalis Kman Esh Vmax [fo] Menton contact marte [eo] You can buy KM me a se - - Umane & km - mare [so] This is inverse plot: Lynd eaver Burk plot Km/uman plot of To use this Yeso] : so from the Slope - km graph gawe get Intercept - Tomar Vmar Scope - Km & mar = km Intercept. Vmart Therefore we get the value of KM from the intercept - I Viman маска intercept

In presence of inhibiton we have - Vmare [s] akutts] x = inhibitor constant x=1+ [I] from inverse plot we KI have ka = inhibitor constant. [7] = concentration of enhibitor Vman. km Vman. T} luman [s.] a So too from the the value of slope we a km = Slope from the previous data we get the value of kan & med Vmax Slope x V man KM Now if you know the concentration. We can (I ie inhibitor get Ki. as 1+ 512 KI ti]/res - a-1
Here I have given you how to do the calculation to find the values. Now you need to draw the graph 1/v vs 1/s by inputting the datas given and get the slopes and intercepts.