We know the Henderson-Hasselbalch equation
pH = pKa + log {[Conjugate Base]/[Acid]}
We have
pKa = 9.24
[Conjugate Base] = [NH3] = 0.21 M
[Acid] = [NH4+] = 0.24 M
By putting the given values in above formula
We get
pH = 9.24 + log (0.21/0.24)
= 9.24 + log(0.875)
= 9.24 - 0.06
= 9.18
So our asnwer is 9.18
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