Question

The weights of a certain brand of candies are normally distributed with a mean weight of 0.8604 g and a standard deviation of 0.052 g. A sample of these candies came from a package containing 459 candies, and the package label stated that the net weight is 391.99. (If every package has 459 candies, the moon weight of the candies 391.9 must exceed 250 =0.8539 g for the net contents to weigh at least 391.99.) a. If 1 candy is randomly selected, find the probability that it weighs more than 0.85399 The probability is (Round to four decimal places as needed.)

Answer 1

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| 6სასტი' Given mean M 20.8604 standard deviation (5) >0.052 Sample size n=459 sample mean @ =394 391.9 20-8539 a) If lcandy ig randomly selected Calculate PCX>0.8539) 2) PC x > 6-8S3) - |- P(x40 853). 31-P(pe20-8539-0.8604) 0.052 = 1- P(Z <=0.125) (2x) - 1-0.4602618 (facem table -0.5497382 ~0.5497 Given mean U-156 std.deviation o=33.2 P (150 < X <211) :P/150-156 X-1 C 33. 2 ő 211-156 -156 83.6 = P(-0.181<7< 1:637) (2x) = P(Z<1.637) - P(Z <-0.181) -0.9491847-0.4281838 = 0.5210009 opporoximately 0.8210. The probability

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