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please answer question 7 using question 5 and the molecular orbital diagram given.

5. Prepare a molecular orbital diagram for BN. You may consider valence orbitals only. Label the atomic orbitals for B and N
5) B-N B 25 -14.05 2-25.56 20-8.30 20-13...18 JO - Y* 1 11-13.18 1 I 2P - 14.05 w as.se T no 25 The Sp wang should be conside
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Answer #1

Bond order = (1/2) × (number of bonding electrons - number      of  antibonding electrons)

No.of bonding electron = 6

No.of antibonding electron = 2

Bond order = (1/2)× (6 -2)

= (1/2) ×(4)

= 2

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