Question

7. Without using hybridization, construct a reasonable molecular orbital diagram showing the interaction between the oxygen and the fluorines for OFs (oxygen is the central atom). Your diagram must account for the following: OFs is diamagnetic. OF, is paramagnetic. relative to OFs, the bond order for OF3 decreases. . relative to OF,, the bond order for OF, does not change. relative to OF, , the bond order for OF, does not change. For full credit, you must: . label the molecular orbitals indicate which orbitals interact (by using dashed lines). . place the electrons into the molecular orbitals. clearly identify the LUMO and the HOMO for OF,' 2p 2s 2p 2s 3 F

Answer 1

Molecular orbitals diagram of OF^+_3 using without hybridization Electronic configuration (E. C) of Oxygen and flourine O_s rightarrow 1s^2 2s^2 2Px^2 2Py^1 2Pz^1 But O^+_B OR O_7 And 3ZF_9 => i.e There 2px of F_3 electron pair with three (2s, 2py, 2pz) different orbital of oxygen atom. Diagram: - (1) In case of OF^+_3 all the orbitals are with pair of electron means daimagnetic (2) In OF^1-_3 means two electron extra which go to the r* with one - one electron show para magnetic (3) Bond order = bonding electron - Anti bonding electron/2 Therefore In case of OF^+_3 = 6 - 0/2 = 3 bond orders \r\n But In case of OF^2+_3 one extra electron out from N.B(non - bonding) orbital which not change the bond order of realtive OF^+_3 and OF^2+_3 (5) It is also the same case like point (4) which not change * And all the point for full credit all ready mention in diagram Note: - LUMO => Lowest unoccupying molecular orbitals. HOMO => occupying molecular orbitals