Question

3:09 × Drill Set 1-new-PHYS 242.docx 2. (i A uniformly charged ring has radius a-0.15m and total charge Q- 24 nC (see figure below) 0 What is the circumference of the ring, and thus the charge per unit length (charge density) of the ring Cm) charge density (ii) To find the potential (voltage) at point (P) distant (along the ring's axis) from the ring center, we can first find the E-field as we did in chapter 21, by considering the contributions to the E-field from an clemental charge on the ring. Symmetry then showed that only the component of the E- field that points in the direction of the axis of the ring (at points on the axis) survives. Hence it is easy to perform the integral O going along the ring axis from to x, to get V(). Alternatively, we already know the petential everywhere of a point charge. So for an clemental charge dq, the contribution to the potential at pont P is: (where) charges in the ring, and obtain an expression for the potential (voltage) V at x (on the ring axis) (Hint: where ρ is charge density, ds is elemental length; Also, , a, r, de not vary as we perform the integration over the charges on the ring. Also, k-9x 10 (SI units)) 5 Open With Print

Answer 1

Alright Dude, If that worked for you... dont forget to give THUMBS UP.(that will work for me!)

If I missed something feel free to leave a comment.
atleast before giving downvote.
and, Thanks for using homeworklib- Smarter way to study.