A solution made with 1.0 gram of copper (11) sulfate in water filled to 100 mL...

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Question

Answer 1

Answer #1

mass of copper sulphate given=1g

molar mass of copper sulphate=159.6g

so number of moles of copper sulphate in the solution=1/159.6 =0.0062 mol

initial volume of solution =100ml =0.1 L

initial concentration= 0.0062mol/0.1 L= 0.062 mol/L =0.062 M

dilution formula: M₁V₁=M₂V₂

M₁=0.062M ,V₁=0.1 L, V₂=250ml =0.250 L,M₂=?

M₂=(M₁V₁)/V₂ =(0.062M*0.1)/0.250 =0.0248 M

Molarity=0.0248M

thank you

Answer 2

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