Question

Calculate the amount of copper (II) sulfate needed to prepare 100. mL of 0.0100 M solution

Answer 1

The equation for Molarity must be rearranged to solve for the moles of solute (CuSO4). The moles of solute can then be converted into grams.

Moles of CuSO₄ = Molarity (moles/L) $\times$ Volume of solution (L)

Moles of CuSO₄ = 0.01 (moles/L) $\times$ 0.1 (L)

Moles of CuSO₄ = 0.001 moles

Now, convert the moles of solute into grams by using the molar mass of CuSO₄.

Cu = 63.549 g/mol

S = 32.065 g/mol

O = 15.999 g/mol

CuSO₄= ( 63.549 + 32.065 + 63.996 ) g/mol = 159.61 g/mol

Grams of CuSO₄ = 0.001 mole $\times$ 159.6 g/mole

Grams of CuSO₄ = 0.1596 g

Hence , The amount of Copper (II) Sulfate needed to prepare 100ml of 0.01 M solution is 159.6 mg