A tube containing 8.00 mL of 0.250 M copper (II) sulfate contains 2.00 x 10^-3 mole of copper (II) sulfate. how many grams of solid copper (II) sulfate would this be equivalent to? using dimensional analysis
we know
number of moles = mass / molar mass
mass = number of moles * molar mass
so,
mass of cuso4 = 2 * 10-3 moles * 159.6 g / mole = 0.319 g
A tube containing 8.00 mL of 0.250 M copper (II) sulfate contains 2.00 x 10^-3 mole...
A student must prepare 500.0 mL of solution containing 3.550 grams of solid copper(II) sulfate. Which of the following statements are FALSE regarding the proper procedure to prepare this solution? I. The 3.550 grams of solid copper(II) sulfate is dissolved in a 500.0-ml volumetric flask containing 500.0 mL of water. II. The 3.550 grams of solid copper(II) sulfate is dissolved in a 500.0-ml volumetric flask containing 400 mL of distilled water before dilution to 500.0-mL. III. The 3.550 grams of...
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S. (10 points) In the laboratory, you have available; solid crystals of copper (II) sulfate pentahydrate, lab balances, plenty of distilled water and access to all standard glassware. Explain with as much detail as you can, how you would prepare exactly 200.0 mL. of a 0.0600 M aqueous solution of copper (II) sulfate pentahydrate (CuSO 5H2O) 0.0600M ML 200.ML 11
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