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PRIVIN BALK NEXT Chapter 26, Problem 069 A converging lens (f = 12.5 cm) is located 36.6 cm to the left of a diverging lens (
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Answer #1

using lens formula for converging

1/f = 1/v - 1/u

1/ 12.5 = 1 / v + 1/28.3

v = 22.39 m/s

now the above image acts as object for diverging lens

object distance of which is given by

u' = 36.6 - 22.39 = 14.21 cm

using lens formula for diverging lens

- 1/8.26 = 1/ v' + 1/14.21

v' = 5.224 cm

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b)

net magnification

m = (v'/u') (v/u) = (5.224 / 14.21)* ( 22.39 / 28.3)

m = - 0.2908

you may neglect negative sign in order to have magnitude only

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Comment before rate in case any doubt, will reply for sure.. goodluck

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