using lens formula for converging
1/f = 1/v - 1/u
1/ 12.5 = 1 / v + 1/28.3
v = 22.39 m/s
now the above image acts as object for diverging lens
object distance of which is given by
u' = 36.6 - 22.39 = 14.21 cm
using lens formula for diverging lens
- 1/8.26 = 1/ v' + 1/14.21
v' = 5.224 cm
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b)
net magnification
m = (v'/u') (v/u) = (5.224 / 14.21)* ( 22.39 / 28.3)
m = - 0.2908
you may neglect negative sign in order to have magnitude only
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Comment before rate in case any doubt, will reply for sure.. goodluck
PRIVIN BALK NEXT Chapter 26, Problem 069 A converging lens (f = 12.5 cm) is located...
Chapter 26, Problem 069 A converging lens (f = 11.6 cm) is located 34.2 cm to the left of a diverging lens (f -4.68 cm). A postage stamp is placed 28.6 cm to the left of the converging lens. (a) Locate the final image of the stamp relative to the diverging lens. (b) Find the overall magnification (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work
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A converging lens (f = 13.0 cm) is located 40.6 cm to the left of a diverging lens (f = -7.18 cm). A postage stamp is placed 49.0 cm to the left of the converging lens. (a) Locate the final image of the stamp relative to the diverging lens. (b) Find the overall magnification.