Question

As part of a study of corporate employees, the director of human resources for PNC Inc. wants to compare the distance traveled to work by employees at its office in downtown Cincinnati with the distance for those in downtown Pittsburgh. A sample of 35 Cincinnati employees showed they travel a mean of 370 miles per month. A sample of 40 Pittsburgh employees showed they travel a mean of 380 miles per month. The population standard deviations for the Cincinnati and Pittsburgh employees are 30 and 26 miles, respectively. At the 0.05 significance level, is there a difference in the mean number of miles traveled per month between Cincinnati and Pittsburgh employees? a. Is this a one-tailed or a two-tailed test? O One-tailed test OTwo-tailed test . State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) The decision rule is to reject HO: C = up if z is ! the interval | _ the interval ( .

Answer 1

- solution Here let sample is cincimati & sample 2 is pittsburgh D Here Holi Fally us Hili falla This is 2-tailed test 2) Here a=o.os, critical value = I 196 The decision rule is reject to if z is not in the interval (-1.96, 196) © Here ni =35, 71=370, 9=30 n2 = uo, ag = 380, 22=26 21-22 - 370-380 = 1.53 Test statistic 2= - d) Here 1.53 ies in the interval (-1.96, 1996) so do not reject to e No, there is not sufficient evidence that there is a difference in mean no. of miles traveled.