Answer
(A) it is a one tailed hypothesis test because the alternate hypothesis is showing a less than symbol
(B) Significance level is 0.03
z critical = NORMSINV(alpha)
= NORMSINV(0.03)
= -1.88
Reject Ho if z < -1.88
(C) z statistic = -2.67 (already calculated)
(D) it is clear that z value is less than -1.88, so we will reject null hypothesis Ho and result is significant
(E) p value = NORMSDIST(z)
set z = -2.67
we get
p value = NORMSDIST(-2.67)
= 0.0038
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> Thank you very much for showing how to do the Excel formulas. I was having a hard time figuring it out and you have helped tremendously. Thank you!!!
Jennifer Wadkins Tue, Mar 23, 2021 7:26 PM