Question

wire A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does. Classify the descriptions by whether they apply to the X or Y electrode. salt bridge x2+ (aq) Y2+ (aq) X electrode Y electrode anode cathode electrons in the wire flow toward it anions from the salt bridge flow toward it cations from the salt bridge flow toward it gains mass loses mass electrons in the wire flow away from it

Answer 1

X electrode	Y electrode
anode	cathode
Electrons in the wire flow away from it	Electrons in the wire flow towards it
Anions in the salt bridge flow towards it	Cations from the salt bridge flow towards it
loses mass	gain mass

Since X is more reactive ,it undergoes oxidation at anode

X(s) ---> X+(aq) +1e- .Thus mass of metal will decrease
These electrons will flow towards cathode the ions there will consume it and undergo
reduction

Y+(aq) +1e- ---> Y(s).thus mass of metal will increase

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