Question

Justify your answer R = 2R R = 2R & R = R 2 The circuit above contains a battery with negligible internal resistance, a closed switch S, and three resistors, each with a resistance of R or 2R. a. i. Rank the currents in the three resistors from greatest to least, with number 1 being greatest. If two resistors have the same current, give them the same ranking. 1 A 3 B 2 Ic ii. Justify your answers. b. i. Rank the voltages across the three resistors from greatest to least, with number 1 being greatest. If two resistors have the same voltage across them, give them the same ranking. I VA 2 VEL Vc ii. Justify your answers. For parts c. through e., use E = 12 V and R = 200 2. c. Calculate the equivalent resistance of the circuit. d. Calculate the current in resistor Rc. e. The switch S is opened, resistor Re is removed and replaced by a capacitor of capacitance 2.0 * 10-6F, and the switch S is again closed. Calculate the charge on the capacitor after all the currents have reached their final steady-state values.

Answer 1

MRA=2R VV WW Sre VA 2V, 22_vc © Equivalent resistance Regn= {x200=533.31 (a vela la la la 1 200 (= 158103A ② @ Lemonza Ro and Re care in parallel Roc= RB Re = QR XR = 2B Rose is in series with RA Equivalent resistance of cirait Reqn = Rathge=2R+ 28 = gee increase is: ic = akik = 1:2 is = ţin = Sm and is from asore . IA 3 IB 2 I A=istic where is=3 Asiazka VAZIARA=3 & (22) = 36 NA UBE [ V3 = iBRE 2 (OR) = & Ve=iRe = 1 FRE=R II In steady stale current through Capactor is zero, so RA and Re are in series . RAC=RATRE= QR+ R = 3R is element the 2003 2x16A Voltage across Re= Witage ! :.Vc = "che=2x10x20 over ! q=charge on capacitor" q=CV = 2x108x 4 = 8x106c i across Capacitor -