Balance by the method of 1/2 reactions: b. O2 (aq) + H2O → OH(aq) + O2(g)
N -2 H-6 O-5 Balance these equations Soat 02 7503 NH₃ + O2 >Noat H₂O Fe(OH)2 + O2 + H2O → Fe(OH)23 Pa Hu PH₂ +P4 Na Hu toa > H₂O₂ t Na NaSO 4 +C Naa St co
Which of the following chemical reactions represents the ionization of water? 0 H2O(l) H2O+(aq) + e- O H+(aq) + OH-(aq)= H2O(l) O H2O(l)-H2O-(aq) 2H20 2H2(g)+ 02(8) O H2O(l)-H'(aq) + OH-(aq)
37. Balance the following equations: a. PbO2(s) —>PbO(s) + O2(g) b. Fe(OH)3(s) —>Fe2O3(s) +H2O(s) C. (NH4)2CO3(s) —>NH3(g)+H20(g) + CO2(g) d. CaCl2(aq) + H2SO4(aq) — CaSO4(s) + HCl(aq) 761
C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l) Given the entropies of the reactions below, calculate the entropy of the chemical explosion at 37 C. 2 H2O2 (aq) ------> 2H2O(l) +O2(g) = +0.4501 kj/mole*k C6H4((OH)2(aq) ------> C6H4O2(aq) + H2(g) = + 0.5033 kj/mole*k 2 H2(g) + O2(g) -----> 2 H2O (l) = -0.327.2 kj/mole*k
Question 6 (1 point) Given: Zn(s) + OH(aq) + H2O(l) + NO3- (aq) --> Zn(OH)42-(aq) + NH3(g) If 8 electrons are transferred in the balanced equation, what is the coefficient of OH-? Ö Ô ô ô 8
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator) HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator) HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
Consider the following reactions: SO32- (aq) + H2O(l) = HSO3_(aq) + OH-(aq) Kb1 = 8.3 x 10-8 | HSO3- (aq) + H2O(l) = H2SO3(aq) + OH-(aq) K12 = 7.6 x 10-13 What is the pH of 1.0 x 10-3 M Na2SO3? Select one: O a. 5.0 O b. 10.5 C. 13.0 O d. 9.0 e. 7.0
Consider the following reactions: Koi = 8.3 x 10-8 SO32-(aq) + H2O(1) = HSO:_(aq) + OH(aq) HSO3- (aq) + H2O(1) = HSO3(aq) + OH-(aq) K12 = 7.6 x 10-13 What is the pH of 1.0 x 10-3 M Na2SO3? Select one: O a. 7.0 b. 9.0 C. 5.0 d. 13.0 o e. 10.5