From equation (4) , we have : [F-] = [H3O+] - [OH-]
Using the value of [OH-] from equation (2), [OH-] = Kw/[H3O+]
[F-] = [H3O+] - Kw/[H3O+] ---(5)
From equation (3) , [HF] =0.05M - [F-]
Replacing the value of [F-] from equation (5)
[HF] = 0.05M - ([H3O+] - Kw/[H3O+]) ----(6)
Ka = [H3O+][F-]/[HF] , putting the values of concentration of HF and F- from equation (5) &(6) .
Ka=[H3O+]{ [H3O+] - Kw/[H3O+]}/{0.05M - [H3O+] - Kw/[H3O+]}
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA...
HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if [HFJinitial 0.05M, then K,=[H,O" ][A]/[HA] Kw=[HO"][OH] 0.05M [HF] +[F] equilibria (1) (2) mass balance (3) charge balance al+LHol L0H] (4) Given the setup above, manipulate the equations so you are left with this equation: Ka [H3O'1{[H,o'j-K[H3O']} / {0.05-[H20*1-K.//H2O]} ( you do not have to distribute the negative in the denominator) HF(aq) + H2O() H0"(aq) + F (aq) EC. 2 H2O() H3O* (aq) + OH(aq) if...
Equations pH=-log[H3O+]; pOH= -log[OH]; pKw=14.00=pH+POH; Ka-[H3O+][A-[HA]; Kb=[BH+][OH-)[B); pKa=-log Ka; Ka. Kb=Kw Constants Ka (HS-)=1x10-19; Ka (HF) 7.2x10-4; Ka ([Al(H20).]+)7.9x10-6; Ka (H3PO4)=7.5x10-2: Ka (HPO42-) =3.6x10-13; Ka (HCI)=Huge; Ka(Na+)=tiny; Ka(Cl-)tiny; Kb(NH3)=1.8x10-5; Kw=1x10-14 1) Calculate the pH of aqueous 0.25M HCl and 0.25M HF solutions. 2) Complete the following tables for aqueous solutions of conjugate acid-base pKa pKb Kb 1.3x10-4 35 3) Complete the following table for aqueous solutions DHL TH+) OH) pOH 1x102 4) Calculate the pH of aqueous 0.15M Ba(OH)2 and...
1. 2. If I have the reaction HF (aq) + H20 (1) = H3O+ (aq) + F (aq), the expression K = (Select] / [Select] (Select] [H20] * [F-] [HF] * [F-] [H3O+]*[F] [HE] [HF] * [H20] [Select] [HE] [HF] * [H20] [H20] [F-) [H3O+] * [HF]
Write a balanced base equation for F"(aq) F (aq) + H20(1) =H30+ (aq) + HF (aq) F"(aq) + H20(1) = H20"(aq) + F(aq) F (aq) + H2O(0) = OH"(aq) + HF(aq) F"(aq) + H20(1)=H*(aq) + HOF(aq) Impossible to determine QUESTION 2 Write a balanced base equation for CH3CH2NH2(aq) CH3CH2NH2(aq) + H2O(1) = H30+ (aq) + CH3CH2NH" (aq) CH3CH2NH2(aq) + H2O(1) = OH(aq) + CH3CH2NH3(aq) CH3CH2NH2(aq) + H2O(1) = H20" (aq) + CH3CH2NH2+(aq) CH3CH2NH2(aq) + H2O(1) = NH4+(aq) + CH3CH2OH(aq) Impossible...
Consider the buffer system of hydrofluoric acid. HF. and its salt. NaF. HF(aq) + H2O() E H 0*(aq) + F(aq) a. The purpose of this buffer system is to: 1. maintain (HF] 2. maintain [F] 3 maintain pH b. The salt of the weak acid is needed to: (1) provide the conjugate base 2. neutralize added 1,0 3. provide the conjugate acid c. If OH is added, it is neutralized by: 1. the salt 2. HO 3. H,00
estion 10 of 65 > Consider the reaction. HF(aq) + KOH(aq) — KF(aq) + H20(1) What is the net ionic equation for the chemical reaction? HF(aq) + K+(aq) + OH(aq) — K+(aq) + F (aq) + H2O(1) O HF(aq) + K+(aq) + OH-(aq) — K+(aq) + F (aq) + H+(1) + OH-(1) O HF(aq) + OH-(aq) —> F-(aq) + H2O(1) HF(aq) + K+(aq) F (aq) + H+(1) HF(aq) + K+(aq) K+(aq) + H2O(1) - 11 of 65 > Calculate either...
< Problem Set #5 (Ch 15) Exercise 15.33 Write an equilibrium expression for each of the following chemical equations involving one or more solid or liquid reactants or products. Part A coz (aq) + H20 (1) = HCO3 (aq) + OH(aq) CO) 0 Kea- HCO, OH ) [HCO, Keq = H0] Keq = HCO, OH | CO Keq = ico HCO3 H20 CO; H0] [COH,0] Нco, е кең= CO HO THỦ, HL0 Submit Request Answer Part B Part B. 2...
HF(aq) reacts with NaOH(aq) according to the reaction represented below. HF(aq) + OH(aq) - H2O(l) + F(aq), K-7.2x 10-4 A volume of 15 mL of 0.40 M NaOH(aq) is added to 25 mL of 0.25 M HF(aq) solution. Assume that volumes are additive. Write up to 8 correct, distinct and relevant facts about this reaction and any other information given. You'll earn 1 point for each correct statement. Five statements will get you full credit. Only the first eight statements...
NaNH2 -CH₃ 2) OH CH3CH2Br H3C-EC-H * * CH3CH2CH2Br NaOH, H2O BH/THE H2, Pt CH3Br LI, NH3 (1) NaBH4 OsO4, NaHSO3, H20 Hz, Lindlar's Catalyst In each reaction box, place the best reagent and conditions from the list below. NaNH2 CH3 CH3CH2Br OH H3C-CC-H - - ker CH₂ + HCl CH3CH2CH2Br HO NaOH, H2O BH/THF CH3BT H2, Pt LI, NH3 (1) NaBH4 OsO4, NaHSO3, H20 Hz, Lindlar's Catalyst
Write the concentration equilibrium constant expression for this reaction. HF(aq)+H2O(1-F (aq)-H,0 (aq)