C6H4(OH)2(aq) + H2O2(aq) ----> C6H4O2(aq) + 2 H2O(l)
Given the entropies of the reactions below, calculate the entropy of the chemical explosion at 37 C.
2 H2O2 (aq) ------> 2H2O(l) +O2(g) = +0.4501 kj/mole*k
C6H4((OH)2(aq) ------> C6H4O2(aq) + H2(g) = + 0.5033 kj/mole*k
2 H2(g) + O2(g) -----> 2 H2O (l) = -0.327.2 kj/mole*k
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