Question

A mass m = 4.700 kg is suspended from a string of length L = 1.270...

A mass m = 4.700 kg is suspended from a string of length L = 1.270 m. It revolves in a horizontal circle. The tangential speed of the mass is 2.243 m/s. What is the angle theta between the string and the vertical (in degrees)?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

[= 1.27m, m=4.7 kg, v= 2.243 mis Thoso - from T Sino = 1 my? (L Sino) 2) also T Coso = mg =) T= mg Coso - (2.243)? i mag tan@

Add a comment
Know the answer?
Add Answer to:
A mass m = 4.700 kg is suspended from a string of length L = 1.270...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A mass m = 4.300 kg is suspended from a string of length L = 1.290...

    A mass m = 4.300 kg is suspended from a string of length L = 1.290 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.743 m/s. What is the angle theta between the string and the vertical (in degrees)?

  • 2. [2pt] A mass m = 9.100 kg is suspended from a string of length L...

    2. [2pt] A mass m = 9.100 kg is suspended from a string of length L = 1.210 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.089 m/s. What is the angle theta between the string and the vertical (in degrees)? Answer: Submit All Answers

  • A mass m = 8.3 kg is suspended from a string of length L = 1.33...

    A mass m = 8.3 kg is suspended from a string of length L = 1.33 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.27 m/s. What is the angle between the string and the vertical (in degrees)?

  • A mass m = 7.9 kg is suspended from a string of length L = 1.15...

    A mass m = 7.9 kg is suspended from a string of length L = 1.15 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 2.80 m/s. What is the angle θ between the string and the vertical (in degrees)?

  • 2. [2] A mass m 8.100 ky is suspended from a string of length vertical (in...

    2. [2] A mass m 8.100 ky is suspended from a string of length vertical (in degrees)? 1.150 m. It revolves in a horirontal circle (see Figure). The tangential speed of the mass is 2.403 ... What is the angle theta between the string and the 3.12pt] Calculate, using Newton's law of gravity, the magnitude of the force of attraction between the Earth and a mass of 33.000 kg on the Earth's surface. The distance to the center of the...

  • A mass M = 4 kg attached to a string of length L = 2.0 m...

    A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle theta θ= 46.5 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?

  • uMassD WebSite × My Blackboard C: × \M physes Capa, ak X Answer: Submit All Answers...

    uMassD WebSite × My Blackboard C: × \M physes Capa, ak X Answer: Submit All Answers A mass m 5.700 kg is suspended from a string of length L-1.570 m. It revolves in a horizontal carcle (see Figure). The tangential speed of the mass is 2.713 ms. What s the angle theta between th 15.[1pt string and the vertical (in degrees)? Answer Submit All Answers

  • A bob of mass m = 0.300 kg is suspended from a fixed point with a...

    A bob of mass m = 0.300 kg is suspended from a fixed point with a massless string of length L = 23.0 cm . You will investigate the motion in which the string traces a conical surface with half-angle θ = 15.0 ∘. What tangential speed v must the bob have so that it moves in a horizontal circle with the string making an angle 15.0 ∘ with the vertical?

  • This mass (m) on a string (of length L) is moving in a horizontal circle. The...

    This mass (m) on a string (of length L) is moving in a horizontal circle. The string makes an angle of 60 degrees with the vertical. (Express your answers in terms of m, L, g, and theta) Find the tension in the string. Find the speed of the mass.

  • A bob of mass m = 0.250 kg is suspended from a fixed point with a...

    A bob of mass m = 0.250 kg is suspended from a fixed point with a massless string of length L = 21.0 cm . You will investigate the motion in which the string traces a conical surface with half-angle θ = 25.0 ∘. What tangential speed v must the bob have so that it moves in a horizontal circle with the string making an angle 25.0 ∘ with the vertical? Express your answer numerically in meters per second.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT