Net force on m along vertical direction
Tcos(theta) = mg
T*cos(60) = mg
Tebsion in the string T = 2mg
From conservation of energy
KE = PE
(1/2)mv^2 = mgh
v^2 = 2gL(1-cos(theta)
v^2 = 2gL(1-cos(60))
v = (gL)^0.5
This mass (m) on a string (of length L) is moving in a horizontal circle. The...
A mass m = 4.700 kg is suspended from a string of length L = 1.270 m. It revolves in a horizontal circle. The tangential speed of the mass is 2.243 m/s. What is the angle theta between the string and the vertical (in degrees)?
2. [2pt] A mass m = 9.100 kg is suspended from a string of length L = 1.210 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.089 m/s. What is the angle theta between the string and the vertical (in degrees)? Answer: Submit All Answers
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A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle theta θ= 46.5 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
A mass m = 0.6kg is attached to a string of length L = 1.5m. The string is pulled in such a way that it makes an angle of 25 degrees with the vertical direction as shown in the figure below. The mass is released from rest. a. Find the speed of as the mass passes through the bottom of its trajectory. b. What is the tension in the string when the mass passes through the bottom of its trajectory?...
A mass m = 8.3 kg is suspended from a string of length L = 1.33 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.27 m/s. What is the angle between the string and the vertical (in degrees)?
A mass m = 7.9 kg is suspended from a string of length L = 1.15 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 2.80 m/s. What is the angle θ between the string and the vertical (in degrees)?
A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle 0 = 44.1 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
4. A small object of mass M is swinging around in a vertical circle held by a massless string of length L, attached to a pivot, as shown. Given that the speed of the mass at the bottom of the circle is Vo, find the tension in the string when the mass is at an angle (theta) with respect to the vertical (see figure) Pivot M
A conical pendulum is formed by attaching a ball of mass m to a string of length L, then allowing the ball to move in a horizontal circle of radius r. The following figure(Figure 1) shows that the string traces out the surface of a cone, hence the name.Part A: Find an expression for the tension T in the string.Express your answer in terms of the variables L,m,r and appropriate constants.Part B: Find an expression for the ball's angular speed?.Express your answer...