A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle theta θ= 46.5 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle 0 = 44.1 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
A mass m = 4.700 kg is suspended from a string of length L = 1.270 m. It revolves in a horizontal circle. The tangential speed of the mass is 2.243 m/s. What is the angle theta between the string and the vertical (in degrees)?
A mass m = 4.300 kg is suspended from a string of length L = 1.290 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.743 m/s. What is the angle theta between the string and the vertical (in degrees)?
A mass m = 7.9 kg is suspended from a string of length L = 1.15 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 2.80 m/s. What is the angle θ between the string and the vertical (in degrees)?
2. [2pt] A mass m = 9.100 kg is suspended from a string of length L = 1.210 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.089 m/s. What is the angle theta between the string and the vertical (in degrees)? Answer: Submit All Answers
This mass (m) on a string (of length L) is moving in a horizontal circle. The string makes an angle of 60 degrees with the vertical. (Express your answers in terms of m, L, g, and theta) Find the tension in the string. Find the speed of the mass.
A mass m = 8.3 kg is suspended from a string of length L = 1.33 m. It revolves in a horizontal circle (see Figure). The tangential speed of the mass is 3.27 m/s. What is the angle between the string and the vertical (in degrees)?
4. A small object of mass M is swinging around in a vertical circle held by a massless string of length L, attached to a pivot, as shown. Given that the speed of the mass at the bottom of the circle is Vo, find the tension in the string when the mass is at an angle (theta) with respect to the vertical (see figure) Pivot M
A rock of mass m = 0.97 kg is attached to a massless string of length L = 0.71 m. The rock is swung in a vertical circle faster and faster up to a speed of v = 2.4 m/s, at which time the string breaks. What is the magnitude of the tension, in newtons, at which the string breaks?
Conical Pendulum A mass attached at the end of a massless string swings around in a horizontal circle (the string sweeps out a cone). Let θ be the angle the string makes with the vertical, l be the length of the string, h is the vertical height of the string, and r is the radius of the circle. So, l is the hypotenuse of a right triangle with h and r as legs, and θ as the upper angle. The...