Question

Do not round intermediate calculations. Give your final answer(s) to three significant figures. Each of the links A B and CD is made of aluminum (E -10.9 x 10 psi) and has a cross-sectional area of 0.22 in2. Knowing that they support the rigid member B C, determine the deflection of point E. 2.8 kip 16 in. 18 in 9 in. n.

Answer 1

here we have

$\sum$B=0

2.8*9=Fcd*27

Fcd=0.9333kip

taking sum of forces  in vertical direction

$\sum$Fy=0

Fab*27=2.8*18

Fab=1.8667 kip

so now

$\delta$B=1.8667*10³*16/10.9*10⁶*.22=12.455*10^-3

$\delta$c=0.9333*10³*16/10.9*10⁶*0.22=6.227*10^-3

and deflection at E is

$\delta$E=$\delta$c+X

$\delta$B-$\delta$c/X=27/18

(12.455-6.227)*10^-3/X=1.5

X=4.152*10^-3

$\delta$E=$\delta$c+x=6.227*10^-3+4.152*10^-3=10.379*10^-3in

so the answer is 10.379*10^-3in or 0.01 in 0.0104 in or 0.010379 in