Question

de KINE 505 Sadying tde Ree of the Boaon of P d Ou Ad Post-Laboratory Questions (Use the spaces provided for the answers and additional paper if necessary.) 1. When you caloulated k in the rate equation for the reaction of KMno, solution and HC-O, solution, you assumed khad the same value under the conditions of determinations 1, 2, and 3. (a) Use the method of initial rates to find the order of the reaction with respect to CIO, and with respect to OH Write the rate equation for the reaction of CIO and OH at 0°C (a) What assumption did you make about the reac- tion of KMnO solution and HC-0, solution in those determinations that allowed you to consider k to be a constant? (b) Would it be sound practice to compare the re- sults of determinations 4-6 when caloulating k? Briefly explain (b) Caloulate the rate constant, k, for the reaction of CIO, und OH al 0 "C 2. Do your experimental data substantiate the nule of thumb regarding the effect on the reaction rate of a 10-degree increase in reaction temperature? Briefly explain (c) Calculate the reaction rate for the reaction CIO and OH at O "C when the initial CIO, and OH con- centrations are 8.25 x 10 molt, and 5.35 x 10 molL, respectively 3. Consider the reaction that occurs when a CIO, so- lution and a solution containing hydroxide ions (OH) are mixed at 0 °C, shown in Equation 18. 2 CIO,(aq)+2 OH (aq) CIO (aq)+ CIO2 (aq)+HO) (Eq. 18) When solutions containing CIO, and OH" in various concentrations were mixed at 0 "C, the following rate data were obtained: initial rate initial initial concentration of CIO, mol for formation of determination concentration of CIO,, molL-s OH, molL number 2.33 x 10 9.34 x 10 1.87 x 10 1.25 x 10 2.50x 10 2.50 x 10 1.30 x 10-3 1.30 x 10 2.60 x 10 3 date secton name
3a, 3b, and 3c please

Answer 1

3 0 finding the rate constant "k Rate = k [elen]? [on] 2. 33x104, k. [1258.602]? (1.30-103] Cork 2.33 x604 Poseba 1.25710-2.]? [(-308103] , By solving we will get Tk,...1472103 3 @ Rate - K Celong” Comi-j! Rate = (1.147+10°) (8.25*103) (5.35*102) = 1.147%209% (8.25) 466-66.354167 417.66 m.com ] Rate = h. 176x 103 / co - Rate of Reaction is a 4. 176010

3@ 2do + 2017 → cloj + clotho . Let us suppose the nate Law is Rok [co, jm Corey" Riek 11.25x 10-23 m [1.30x163]= 2.33x6674 Rz z k [2.50 x 102] [1.30x13?)". 9-34x604 R3 = k [2.50x1027m (2.60 x 4633": 1.87 x<0-3• (1.50x102) Poetry ... [m=27 Like Wise By doing Red we will get In=11. a The Order of reaction with respect to clan is on Ort is Therefore the Rate Equation is Rate = k [cle] [orij" TRate = K[co] [ot]' ]