use:
pH = -log [H+]
4.833 = -log [H+]
[H+] = 1.469*10^-5 M
HA dissociates as:
HA -----> H+ + A-
0.579 0 0
0.579-x x x
Ka = [H+][A-]/[HA]
Ka = x*x/(c-x)
Ka = 1.469*10^-5*1.469*10^-5/(0.579-1.469*10^-5)
Ka = 3.727*10^-10
Answer: 3.73*10^-10
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