Here we use the concept of force of attraction between two end of the charges suitable method would be using coloumbs law to determine the force
To determine the effective value of spring we use hooke's law
F=k x
A molecule of DNA is 2.05 micrometers long. The ends of the molecule become singly ionized:...
A molecule of DNA (deoxyribonucleic acid) is 2.18 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.09% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.20 µm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.28% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.28 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.28% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.28 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.03% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.00 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.20% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.01 um long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 0.97% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.07 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.02% upon becoming charged. Determine the effective spring constant of the molecule.
A molecule of DNA (deoxyribonucleic acid) is 2.16 um long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.30% upon becoming charged. Determine the effective spring constant of the molecule. N/m
A molecule of DNA (deoxyribonucleic acid) is 2.18 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.31% upon becoming charged. Determine the effective spring constant of the molecule. THE ANSWER IS NOT 1.696E-9
A molecule of DNA (deoxyribonucleic acid) is 2.06 μm long. The ends of the molecule become singly ionized: negative on one end, positive on the other. The helical molecule acts like a spring and compresses 1.34% upon becoming charged. Determine the effective spring constant of the molecule N/m Need Help? Read lt